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OlgaM077 [116]
2 years ago
9

A colony of ants carried away 16 of your muffins. That was 4/7 of all of them! With how many did you start?​

Mathematics
1 answer:
mariarad [96]2 years ago
8 0

You started with a total of 28 muffins

<h3>How to determine the amount you started with?</h3>

From the question, the given parameters are:

Proportion carried away = 16 of the total muffins

Proportion carried away = 4/7 of the total muffins

The above parameters implies that

4/7 of the total muffins = 16

Represent the amount you started with x

So, we have the following representation

4/7 of x = 16

Express as products

4/7x = 16

Make x the subject

x = 7 * 16/4

Evaluate

x = 28

Hence, the total number of muffins is 28

Read more about proportions at

brainly.com/question/16828793

#SPJ1

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Step-by-step explanation:

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Find the missing number. 4/5 = ?/45
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Meghan went out to lunch. Her food costs $11.62. A 6% sales tax was
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$12.31

Step-by-step explanation:

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3 years ago
The results of a national survey showed that on average, adults sleep 6.7 hours per night. Suppose that the standard deviation i
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Answer:

a) Atleast 75%

b) Atleast 88.9%

c) 95%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.7

Standard Deviation, σ = 1.6

Chebyshev's Theorem:

  • Atleast 1 - \dfrac{1}{k^2} percent of data lies within k standard deviation of mean.

Empirical Rule:

  • Almost all the data lies within 3 standard deviation for a normal data.
  • Around 68% of data lies within 1 standard deviation of mean.
  • Around 95% of data lies within 2 standard deviation of mean.
  • Around 99.7% of data lies within 3 standard deviations o mean.

a) minimum percentage of individuals who sleep between 3.5 and 9.9 hours

3.5 = \mu - 2\sigma = 6.7 - 2(1.6)\\9.9 = \mu + 2\sigma = 6.7 + 2(1.6)

We have to find the percent of data lying within 2 standard deviation of mean.

Putting k =  2

1 - \dfrac{1}{(2)^2} = 0.75 = 75\%

Atleast 75% of of individuals who sleep between 3.5 and 9.9 hours.

b) minimum percentage of individuals who sleep between 2.7 and 10.7 hours

2.7 = \mu - 3\sigma = 6.7 - 3(1.6)\\10.7 = \mu + 3\sigma = 6.7 + 3(1.6)

We have to find the percent of data lying within 3 standard deviation of mean.

Putting k =  3

1 - \dfrac{1}{(3)^2} = 0.889 = 88.9\%

Atleast 88.9% of of individuals who sleep between 2.7 and 10.7 hours.

c)  percentage of individuals who sleep between 3.5 and 9.9 hours per day.

Thus, we have to find the percentage of data lying within 2 standard deviation.

By empirical rule, around 95% of data lies within 2 standard deviation.

Thus, 95% of of individuals who sleep between 3.5 and 9.9 hours.

This is higher than the percentage obtained from Chebyshev's rule.

4 0
3 years ago
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