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inna [77]
3 years ago
14

Rewrite the following as a base-ten numeral: 3(10)^3+5(10)^2+6(10)

Mathematics
2 answers:
Setler [38]3 years ago
8 0

3000 + 500 + 60 = 3560

_____

Your calculator can help you out here if you really have no idea that the exponent of 10 tells you the number of zeros: 10^3 = 1000.

schepotkina [342]3 years ago
3 0

Answer:

3560

Step-by-step explanation:

3(10)^3+5(10)^2+6(10)

3×10^{3} +5×10^{2}+6×10

We have to solve the above equation

3×10^{3}= 3×1000=3000

5×10^{2}=5×100= 500

6×10=60

3×10^{3} +5×10^{2}+6×10

=3000+ 500+60

=3560

Hence, the correct answer is 3560

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Solve the system.
svetoff [14.1K]

Answer:

(0, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y + 5x = 1

5y - x = 5

<u>Step 2: Rewrite Systems</u>

y + 5x = 1

  1. Subtract 5x on both sides:                    y = 1 - 5x

<u>Step 3: Redefine Systems</u>

y = 1 - 5x

5y - x = 5

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitution in <em>y</em>:                      5(1 - 5x) - x = 5
  2. Distribute 5:                             5 - 25x - x = 5
  3. Combine like terms:                5 - 26x = 5
  4. Isolate <em>x</em> term:                          -26x = 0
  5. Isolate <em>x</em>:                                   x = 0

<u>Step 5: Solve for </u><em><u>y</u></em>

  1. Define equation:                    5y - x = 5
  2. Substitute in <em>x</em>:                       5y - 0 = 5
  3. Subtract:                                 5y = 5
  4. Isolate <em>y</em>:                                 y = 1
8 0
2 years ago
For a beach trip, Sarai spends $9 on sunscreen, $18 on beach towels, $22 on food, $9 on a first aid kit, and $11 on sand toys.
AVprozaik [17]
$9 represents the Mode
Mode is data that occurs the most
6 0
3 years ago
Person 1 writes internal operating procedures 3 times faster than Person 2. Most of the procedures took 30 minutes each to creat
ad-work [718]

Person 1 takes 3 hour 10 minutes to complete 9 procedures

<em><u>Solution:</u></em>

From given question,

Person 2 takes 30 minutes per procedure

Person 1 writes internal operating procedures 3 times faster than Person 2

So we get, Person 1 takes 3 times faster than Person 2

Person 1 takes 10 minutes per procedure

But two of the procedures for Person 1 took an hour each

So person 1 takes 60 minutes each for two of procedures ( since 1 hour = 60 minutes )

<em><u>Calculate how long it took Person 1 to complete 9 procedures:</u></em>

So for first 7 procedures person 1 would take 10 minutes per procedure and for last two procedures person 1 would take 60 minutes per procedure

time $=7$ procedures $\times \frac{10 \text { minutes }}{1 \text { procedure }}+2$ procedure $\times \frac{60 \text { minutes }}{1 \text { procedure }}$

time=70 minutes +120minutes\\\\time=190minutes

We know that,

1 hour = 60 minutes

Therefore,

190 minutes = 60 minutes + 60 minutes + 60 minutes + 10 minutes

190 minutes = 1 hour + 1 hour + 1 hour + 10 minutes = 3 hour 10 minutes

Therefore Person 1 takes 3 hour 10 minutes to complete 9 procedures

7 0
3 years ago
What is the volume of a sphere with a radius of 12 inches? Use 3.14 for x.
likoan [24]

the volume of a sphere with a radius of 12 inches is 602.88

8 0
3 years ago
What’s the equation for a line passing through points (-1, 4.5) and (6, 8)?
san4es73 [151]

Answer:

<em>Given </em><em>points </em><em>(</em><em> </em><em>-</em><em>1</em><em> </em><em>,</em><em> </em><em>4</em><em>.</em><em>5</em><em> </em><em>)</em><em> </em><em>and </em><em>(</em><em> </em><em>6</em><em> </em><em>,</em><em> </em><em>8</em><em> </em><em>)</em>

Step-by-step explanation:

<em>first </em><em>we </em><em>should </em><em>calculate </em><em>slope </em>

<em>Slope </em><em>(</em><em> </em><em>m</em><em>) </em>

<em>=</em><em> </em><em>(</em><em> </em><em>y2 </em><em>-</em><em> </em><em>y1</em><em>) </em><em> </em><em>/</em><em> </em><em>(</em><em> </em><em>x2</em><em> </em><em>-</em><em> </em><em>x1</em><em>) </em>

<em>=</em><em> </em><em>(</em><em> </em><em>8</em><em> </em><em>-</em><em> </em><em>4</em><em>.</em><em>5</em><em> </em><em>)</em><em> </em><em>/</em><em> </em><em>(</em><em> </em><em>6</em><em> </em><em> </em><em>+</em><em> </em><em>1</em><em> </em><em>)</em>

<em>=</em><em> </em><em>3</em><em>.</em><em>5</em><em>/</em><em>7</em>

<em>=</em><em> </em><em>0</em><em>.</em><em>5</em>

<em>Now </em><em>the </em><em>equation </em><em>of </em><em>line </em><em>is </em><em>given </em><em>by </em>

<em>y </em><em>-</em><em> </em><em>y1 </em><em>=</em><em> </em><em>m </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>x</em><em>1</em><em> </em><em>)</em>

<em>y </em><em>-</em><em> </em><em>4</em><em>.</em><em>5</em><em> </em><em>=</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>(</em><em> </em><em>x </em><em>+</em><em> </em><em>1</em><em> </em><em>)</em>

<em>(</em><em> </em><em>y </em><em>-</em><em> </em><em>4</em><em>.</em><em>5</em><em> </em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>(</em><em> </em><em>x </em><em>+</em><em> </em><em>1</em><em>)</em>

<em>y </em><em>-</em><em> </em><em>4</em><em>.</em><em>5</em><em> </em><em>=</em><em> </em><em>0</em><em>.</em><em>5</em><em>x</em><em> </em><em>+</em><em> </em><em>0</em><em>.</em><em>5</em>

<em>y </em><em>=</em><em> </em><em>0</em><em>.</em><em>5</em><em>x</em><em> </em><em>+</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>+</em><em> </em><em>4</em><em>.</em><em>5</em>

<em>y </em><em>=</em><em> </em><em>0</em><em>.</em><em>5</em><em>x</em><em> </em><em>+</em><em> </em><em>5</em>

3 0
3 years ago
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