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3 years ago

Planes Q and R are parallel. Lines a and b are shown on planes Q and R, respectively.

Mathematics

2 answers:

Vlad [161]3 years ago

8 0

Answer: I have included an image of the correct answer.

They are skew lines

AveGali [126]3 years ago

5 0

Answer:

Skew Lines

Step-by-step explanation

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PLEASE I NEED HELP, DUE IN 1hr!!!!

cricket20 [7]

Answer:

$137,339.88

Step-by-step explanation:

Here is the equation for compound interest: A=P(1+(r/n))^nt

where A=amount of money, P=principal, r= rate in decimal, n=number of times compounded per t, and t=time

In this case:

A=$250,000

P= ?

r= 0.04

n= 12 month/yr

t= 15 yrs

You can manipulate the equation to solve for P:

P=A/[(1+(r/n))^nt]

Plug in variables then solve:

P= $\frac{250,000}{(1+\frac{0.04}{12})^{12*15} }$

P=137339.8761 = $137,339.88

6 0

3 years ago

Number 6 part a & b Number 7 Please & thank you

miv72 [106K]

Answer:

6- Part A: $750a+1200r=1000000$

Part B: $1065a+876r=1000000$

Solution of the system: $a\approx521.739\;\;\;\;b\approx507.246$

Step-by-step explanation:

Part A:

In words, the equation is formed like this:

Total kg of Arabica + Total kg of Robusta = Total kg of coffee

Now, the total of each yield is calculated by the product of kg/hectare and number of hectares. Thus, the equation is:

$750a+1200r=1000000$

Part B:

In words:

Arabica's worth + Robusta's worth = plantation worth

Each yield's worth is given by the product of the price per kg and the corresponding production. So, the equation is:

$1.42(750a)+0.73(1200r)=1000000\\1065a+876r=1000000$

3 0

2 years ago

Choose the equation of the horizontal line that passes through the part point (1,-5)

vladimir2022 [97]

We know is a horizontal line, so, if it passes through 1,-5, it also passes through "whatever", -5, like 20, -5 or 1000000, -5, or -100000000, -5 and so on.

so, let's pick another point say -7, -5, check the picture below, and let's check about the equation that runs through it,

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 1 &,& -5~) 
% (c,d)
&&(~ -7 &,& -5~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-5-(-5)}{-7-1}
\\\\\\
\cfrac{-5+5}{-7-1}\implies \cfrac{0}{-8}\implies 0
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=0(x-1)
\\\\\\
y+5=0\implies y=-5$