Answer:
6
Step-by-step explanation:
because i just know it lol
If we draw the contingency table of x (vertical) against y (horiz.), we have a square.
For n=4, we have (legend: < : x<y = : x=y > : x>y
y 1 2 3 4
x
1 = < < <
2 > = < <
3 > > = <
4 > > > =
We see that there are n(n-1)/2 cases of x<y out of n^2.
Therefore,
p(x<y)=n(n-1)/(2n^2)=(n-1)/(2n)
However, if the sample space is continuous, it will be simply p(x<y)=1/2.
<u>Answer:</u>
20 -20 0-15 0-5
<u>Step-by-step explanation:</u>
The original graph
<h3>X Y</h3><h3>-25 -10</h3><h3>-5 10</h3><h3>5 15</h3><h3 />
<u>Hope this helps you :)</u>
Answer:
The constant of variation is $1.50
Step-by-step explanation:
Given
Point 1 (1,2)
Point 2 (5,8)
Required
Constant of Variation
Though the graph would have assisted in answering the question; its unavailability doesn't mean the question cannot be solved.
Having said that,
the constant variation can be solved by calculating the gradient of the graph;
The gradient is often represented by m and is calculated as thus

Where

By substituting values for x1,x2,y1 and y2; the gradient becomes




Hence, the constant of variation is $1.50
Answer:
<h2>x = 2</h2>
Step-by-step explanation:
2x + 6 = 6 + 2x
4 + 6 = 6 + 4
10 = 10