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zhuklara [117]
3 years ago
9

I need your help plz say fast this answer​

Mathematics
1 answer:
nikdorinn [45]3 years ago
4 0

Answer:

not exactly an answer but...

Step-by-step explanation:

5y^(2)-9y+6y^((3)/(2))-5y^((1)/(2))+125 = 0 is an equation i came up with. it's un-factorizable though

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A tank hold a volume of 32m3 what is the new volume of an enlarged tank of the scale factor is 5 ?
kirill [66]

Answer:

The new volume of an enlarged tank is 4000m³

Step-by-step explanation:

The scale factor has to be multiplied by the width, length and height so we will have to multiply it 3 times

h * w * l = 32 m³

(h*5) * (w*5) * (l*5)

if we rearrange the multiplications

(h * w * l) * 5 *5 * 5 =

v * 5 * 5 * 5 =

32m³ * 5 *5 *5 = 4000m³

4 0
4 years ago
Need help with this problem, it's got me stuck PLZ
faust18 [17]

24x^2 +25x - 47                     53

----------------------- = -8x -3 - ---------------

ax-2                                     ax-2

add 53/ax-2 to each side

24x^2 +25x - 47+53                    

-----------------------         = -8x -3

ax-2                                    

24x^2 +25x +6                  

-----------------------         = -8x -3

ax-2      

multiply each side by ax-2

24x^2 +25x +6   = (ax-2) (-8x-3)

multiply out the right hand side

24x^2 +25x +6  = -8ax^2 +16x-3ax +6

24 = -8a      25 = 16 -3a

a = -3          9 = -3a

                   a = -3


Choice B

6 0
3 years ago
What is a reasonable estimate for the problem? 3 3/4 x -2/5
Airida [17]

Answer:

You can not break that down any further if x does not equal anything and the equation is not equal to anything.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What number is the dividend in the division problem below?
Paha777 [63]

Answer:

30 = 6×5

The dividend is 30.

:)

6 0
3 years ago
Use Gauss-Jordan elimination to solve the following linear system.
marysya [2.9K]
Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]
mulstiply 2nd row by -1 and add to 3rd
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]
divde last row by 2
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 2rd row by 6 and add to top one
\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 1st row by -1 and add to 2nd
\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]
divide 2nd row by -3
\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]
mulstiply 2nd row by -1 and add to 1st row
\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]
divide 1st row by -3
\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]

rerange
\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer
7 0
3 years ago
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