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eduard
3 years ago
15

A rectangle is formed by placing two identical squares side by side. The area of the rectangle is 32 2 centimeters. What is the

area of one square?
Mathematics
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

16 cm squared

Step-by-step explanation:

Assuming the length of the square is x

We get that the length of rectangle is 2x and width is x.

Using formula of area:

32.= 2x * x

32/2 = x * x

16 = x * x

X = 4cm.

So area of squarr is

X * x= 16 cm ^2

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No, because it does not have a constant rate of change

Step-by-step explanation:

look at the changes of the y values when going from one x value to the next.

x always changes by 1.

but y changes by +7, +5, +6.

the change rate is the ratio y/x.

as we can see, this changes in each interval.

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Plz answer!! ASAP!!
Wittaler [7]

(1) ∠ABC = 65°, ∠DBE = 65°, ∠CBE = 115°, ∠ABD = 115°

(2) ∠ABC = 62°, ∠DBE = 62°, ∠CBE = 118°, ∠ABD = 118°

Solution:

(1) In the given image ABC and DBE are vertical angles.

<u>Vertical angle theorem:</u>

If two angles are vertical then they are congruent.

⇒ ∠ABC = ∠DBE

⇒ 3x° + 38° = 5x° + 20°

Arrange like terms one side.

⇒ 38° – 20° = 5x° – 3x°

⇒ 18° = 2x°

⇒ x° = 9°

∠ABC = 3(9°) + 38° = 65°

∠DBE = 5(9°) + 20° = 65°

Adjacent angles in a straight line = 180°

⇒ ∠ABC + ∠CBE = 180°

⇒ 65° + ∠CBE = 180°

⇒ ∠CBE = 115°

∠ABD and ∠CBE are vertical angles.

∠ABD = 115°

(2) In the given image ABC and DBE are vertical angles.

⇒ ∠ABC = ∠DBE

⇒ 4x° + 2° = 5x° – 13°

Arrange like terms one side.

⇒ 13° + 2° = 5x° – 4x°

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Adjacent angles in a straight line = 180°

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⇒ 62° + ∠CBE = 180°

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∠ABD and ∠CBE are vertical angles.

∠ABD = 118°

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