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aksik [14]
3 years ago
10

Find the difference. 10 - 14

Mathematics
1 answer:
Leni [432]3 years ago
8 0

Answer:

like regular subtraction? or  

what

Step-by-step explanation:

10-14= -4 very confused on what you asking

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Read and answer questions
Rainbow [258]

If a college has 17 tutors to be appointed among the students in four departments, and the number of students in each department is 315, 310, 105 and 80 respectively, the Standard Divisor is 47.647

As per the question statement, a college has 17 tutors to be appointed among the students in four departments, and the number of students in each department is 315, 310, 105 and 80 respectively.

We are required to calculate the Standard Divisor of the above mentioned problem.

To solve this question, we need to know the formula to calculate the standard divisor, which goes as,

Standard Divisor = [(Total Population)/(Number of Candidates)]

Here, the total population of students = (315 + 310 + 105 + 80) = 810

And, the number of teachers to be appointed = 17 (given)

Therefore, Standard Divisor  = (810 / 17) = 47.647

  • Standard Divisor: In Mathematics, standard divisor is the quotient of the total population divided by the number of seats (or other allocations) to be distributed.

To learn more about Standard Divisor, click on the link below

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5 0
1 year ago
3. 3(2x - 1) + 4 = 3 - 5(1 - x)<br><br>​
yarga [219]

Answer:

= -3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A line tangent to a circle and a radius of the same circle intersect at the point of tangency to create an angle of what measure
aliya0001 [1]

A theorem states that, given a circle with center C and a point P on the circumference, the tangent line through P and the radius CP are perpendicular.

So, the answer is 90 degrees.

3 0
3 years ago
Show all work and provide necessary descriptions
masya89 [10]

Let

P=(P_x,P_y),\quad Q=(Q_x,Q_y)

If M is the midpoint, the x and y coordinates of M are the average of the x and y coordinates of P and Q:

M=\left(\dfrac{P_x+Q_x}{2},\ \dfrac{P_y+Q_y}{2}\right)

We can solve this expression for the coordinates of Q:

M_x = \dfrac{P_x+Q_x}{2} \implies Q_x = 2M_x-P_x

M_y = \dfrac{P_y+Q_y}{2} \implies Q_y = 2M_y-P_y

Plug in the values for the coordinates of M and P to get

Q_x = 2M_x-P_x = 2\cdot 5-11 = 10-11=-1

Q_y = 2M_y-P_y = 2\cdot (-2) - (-10) = -4+10=6

5 0
3 years ago
Let f(x) = x + 8 and g(x) = x2 - 6x - 7. Find f(g(2)).
Alex
We are given with two functions: f(x) = x + 8 and g(x) = x2 - 6x - 7. In this problem, the value of f(g(2)) is asked. We first substitute g(x) to f(x) resulting to f(x2 - 6x - 7) = x2 - 6x - 7 + 8 = x2 - 6x  + 1. If x is equal to 2, then <span>f(g(2)) = 2^</span>2 - 6*2  + 1 equal to -7.
6 0
3 years ago
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