C/3 = 6 1/7
Multiply 3 to both sides:
C = 6 1/7 * 3
Convert 6 1/7 into an improper fraction:
C = 43/7 * 3
Multiply 3 to the numerator:
C = 129/7
Convert back into a mixed number:
C = 18 3/7
log(3x) = log(2x-4)
taking antilog of both sides:
3x = 2x - 4
3x - 2x = -4 [subtracting 2x from both sides]
x = -4
and we're done already!
Answer:
I think ∆5 is the correct Ans
Answer: [ number 1 & 2are a rule of sequence ] 1: Write a rule for the sequence. 2,6,10,14 a; start with two and subtract four repeatedly b; start with four and add two repeatedly ** c; start with two and add four repeatedly d; start with two and add one , add two.
Step-by-step explanation:
