Answer:
(x+1)^2+(y-5)^2=13
Step-by-step explanation:
If <span>y = -x + 7, and (-1,y) is on the graph, then the following is true: y=-(-1) + 7, or y=8.
Thus, y = a0 = 8.</span>
Step-by-step explanation:
The equation of line A:
y-1=0, 5x-3
y=0, 5x-2. Hence its gradient is 0,5
For line B, its you intercept is -8, so y=mx-8.
When x = -4, y=-4m -8 =0 as shown in the graph. This means that m = -2.
Since |-2| > |0, 5|, line B is steeper than line A.
The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1
If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1
If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)
If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)
however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1
If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1
and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)
Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
I think the answer will be A
