PLEASE HELP ME!!! I AM FAILING AND NEED THE ANSWERS!!! I WILL GIVE BRAINLIEST, PLEASE!!!!!

The table shows how many males and females attended two different movies. How would you find the joint relative frequency of bei

kirza4 [7]

Answer:

B. Divide 124 by 229.

Step-by-step explanation:

Given the table

$\begin{array}{cccc}&\text{Action}&\text{Drama}&\text{Total}\\ \\\text{Male}&105&124&229\\ \\\text{Female}&99&151&250\\ \\\text{Total}&204&275&479\end{array}$

The <u>joint relative frequency</u> is the ratio of the frequency in a particular category and the total number of data values.

The total number of males $=229$

The number of males that like drama $=124$

So, to find the joint relative frequency of being male and attending a drama movie, you should divide 124 by 229.

8 0

3 years ago

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Solve the system using elimination.

Shalnov [3]

Answer:

After simplifying we get (x,y) as (1,3).

Step-by-step explanation:

Given:

$x+7y=22$ ,

$x-7y=-17$

We need to use elimination method to solve the and simplify the equations.

Solution;

Let $x+7y=22$ ⇒ equation 1

Also Let $4x-7y=-17$ ⇒ equation 2

Now by solving the equation we get;

first we will Add equation 2 from equation 1 we get;

$(x+7y)+(4x-7y)=22+(-17)\\\\x+7y+4x-7y=22-17\\\\5x=5$

Now Dividing both side by 5 using division property of equality we get;

$\frac{5x}{5}=\frac{5}{5}\\\\x=1$

Now Substituting the vale of x in equation 1 we get;

$x+7y=22\\\\1+7y=22$

subtracting both side by 1 using subtraction property of equality we get;

$1+7y-1=22-1\\\\7y=21$

Now Dividing both side by 7 using division property of equality we get;

$\frac{7y}{7}=\frac{21}{7}\\\\y=3$

Hence we can say that, After simplifying we get (x,y) as (1,3).

4 0

2 years ago

Assume V and W are finite-dimensional vector spaces and T is a linear transformation from V to W, T: Upper V right arrow Upper

scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

T(c_1v_1) + T(c_2v_2) +.... + T(c_pv_p) = 0

T(c_1v_1+ c_2v_2 ... c_pv_p) = 0

But also T(0) = 0 and since T is one-to-one, it follows that c_1v_1 + c_2v_2 +.... + c_pv_p = O.

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.

8 0

3 years ago

Please help fast and show your work

Wittaler [7]

Step-by-step explanation:

85-83=2

2/85×100

3 0

3 years ago

Help pleaseee!!!!!!!!!!!!

Veronika [31]

Answer:

C brainliest?

Step-by-step explanation:

5 0

3 years ago

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