Question

Find the average of the function over the given interval. f(x) = x3 ? x over [0, 2]

Answer 1

$\displaystyle\frac1{2-0}\int_0^2(x^3-x)\,\mathrm dx=\frac12\left(\frac14x^4-\frac12x^2\right)\bigg|_{x=0}^{x=2}=1$