13 can only be divided evenly by 1 and<span> 13. its a prime number
</span>
Would assume it to be 36x² - 25 = 0
<span>36x² - 25 = 0
</span>
<span>(6x)² - 5</span>²<span> = 0</span>
(6x + 5)(6x - 5) = 0 By difference of two squares.
6x + 5 = 0 or 6x - 5 = 0
6x = -5 6x = 5
x = -5/6 x = 5/6
x = +5/6 or - 5/6
Answer:

Step-by-step explanation:
First, transform the fraction inside the square root into the following:
.
Next, you can take the square root of 36 (
), which is 6 (
).

Then, you can take the square root of 169 (
), which is 13 (
)

270(pi/180)=3pi/2=theta
theta*radius=arc length
(3pi/2)(14)=65.9734 yds
Answer:
-6
Step-by-step explanation:
The y-int is the point where the line crosses the y axis
Going by intervals of 2, it crosses at -6
:)