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3 years ago

I need help please

Mathematics

1 answer:

AysviL [449]3 years ago

3 0

Answer:

-6

Step-by-step explanation:

The y-int is the point where the line crosses the y axis

Going by intervals of 2, it crosses at -6

You might be interested in

Which represents the solution set of 5(x+5) < 85?

Maru [420]

Answer:

$\Huge \boxed{X$

Step-by-step explanation:

To solve this problem, first you have to isolate it on one side of the equation. Remember to solve this problem, find represents the solution of 5(x+5)<85.

First, you divide by 5 from both sides.

$\displaystyle \frac{5(x+5)}{5}$

Solve.

$\displaystyle 85\div5=17$

$\displaystyle x+5$

Next, subtract 5 from both sides.

$\displaystyle x+5-5$

Solve.

$\displaystyle 17-5=12$

As a result, the correct answer is x<12.

<h2>Hope this helps! </h2><h2 /><h2>Have a wonderful blessing day! :)</h2><h2 /><h2>Good luck! :)</h2>

3 0

3 years ago

Which expression represents the phrase "15 less than the current amount"?

Leya [2.2K]

Answer:

C is the answer n is the current amount your just taking way 15

hope this helps

have a good day :)

Step-by-step explanation:

3 0

3 years ago

I NEED HELP PLZ ( WILL GIVE BRAINLYIST) ( NO LINKS)

AlladinOne [14]

9514 1404 393

Answer:

66 cm²

Step-by-step explanation:

The area of the polygon is the sum of the areas of the triangle and the rectangle it sits on. The dimensions of the triangle can be found by examining the top/bottom dimensions shown and the left/right dimensions shown.

The width (base) of the triangle is the difference between the lengths of the bottom and top horizontal lines: (12 -9) cm = 3 cm.

The height of the triangle is the difference between the lengths of the left and right sides of the figure: (9 -5) cm = 4 cm.

The dimensions of the rectangle are shown a the bottom and the left sides of the figure.

triangle area = 1/2bh = 1/2(3 cm)(4 cm) = 6 cm²

rectangle area = LW = (12 cm)(5 cm) = 60 cm²

Total polygon area = 6 cm² + 60 cm² = 66 cm²

4 0

3 years ago

A contractor is installing tiles on a floor that measures 132 x 216 inches. If each tile measures 4 x 4 inches, how many tiles w

Kay [80]

Answer:

1782 tiles

Step-by-step explanation:

Given that:

Dimension fo floor = 132 x 216 inches

Area of floor = 132 * 216 = 28512 in²

Dimension of tiles = 4 * 4 inches

Area of tiles = 4 * 4 = 16 in²

Number of tiles needed to cover floor :

Area of floor / Area of tiles

28512 in² / 16 in²

= 1782 tiles

5 0

3 years ago

1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.

xxTIMURxx [149]

First, rewrite the equation so that <em>y</em> is a function of <em>x</em> :

$x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}$

(If you were to plot the actual curve, you would have both $y=x^{2/3}$ and $y=-x^{2/3}$ , but one curve is a reflection of the other, so the arc length for 1 ≤ <em>x</em> ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

$\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx$

We have

$y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}$

Then in the integral,

$\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx$

Substitute

$u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx$

This transforms the integral to

$\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du$

and computing it is trivial:

$\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)$

We can simplify this further to

$\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}$

7 0

3 years ago

I need help please ​

I need help please