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zhuklara [117]
1 year ago
8

What is the positionof C on the number line and how can i write the answer as a fraction or mixed number

Mathematics
1 answer:
Julli [10]1 year ago
3 0

Answer:

1/2

Explanation:

Let us redraw the number line and point C.

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I need help right now please!<br> I have 2 questions!
yKpoI14uk [10]
1 is 28
2 is 13, 84, 85

Figure both by the Pythagorean Theorem<span />
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Is for over two and 20/6 proportions
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No they're not proportional, and it's four*.
4/2 = 2
20/6 = 3.333333333334 or 3 1/3
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Robert says his better long jump was about 1 foot farther than May's better long up. Is he correct? Explain.
Alborosie
We need mor information to tell what there best long jumps are
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Help appreciated on question in image!<br> Thanks:)
Verdich [7]

Answer:

x=-1,\:x=-7,\:x=i,\:x=-i

Step-by-step explanation:

Considering the equation

x^4+8x^3+8x^2+8x+7=0

Solving

x^4+8x^3+8x^2+8x+7

\mathrm{Factor\:}x^4+8x^3+8x^2+8x+7:\quad \left(x+1\right)\left(x+7\right)\left(x^2+1\right)

As

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=7,\:\quad a_n=1

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:7,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:7}{1}

-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1

=\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]

Solving

\frac{x^4+8x^3+8x^2+8x+7}{x+1}

=x^3+7x^2+x+7

Putting \frac{x^4+8x^3+8x^2+8x+7}{x+1} =  x^3+7x^2+x+7 in equation [A]

So,

\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]

=\left(x+1\right)x^3+7x^2+x+7

As

x^3+7x^2+x+7=\left(x+7\right)\left(x^2+1\right)

So,

Equation [A] becomes

=\left(x+1\right)\left(x+7\right)\left(x^2+1\right)

So,  the polynomial equation becomes

\left(x+1\right)\left(x+7\right)\left(x^2+1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)\mathrm{Solve\:}\:x+1=0:\quad x=-1

\mathrm{Solve\:}\:x+7=0:\quad x=-7

\mathrm{Solve\:}\:x^2+1=0:\quad x=i,\:x=-i

\mathrm{The\:solutions\:are}

x=-1,\:x=-7,\:x=i,\:x=-i

Keywords: polynomial equation

Learn polynomial equation from brainly.com/question/12240569

#learnwithBrainly

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3 years ago
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the area of a square poster is 30 in square. Find the length of one side of the poster to the nearest tenth of an inch​
insens350 [35]

Answer:

x = 5.5 (nearest tenth)

Step-by-step explanation:

let x be the length of 1 side

given area of square poster is 30 in²

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Area = (length of 1 side )²

hence

30 = x²

x = √30

x = 5.4772

x = 5.5 (nearest tenth)

6 0
3 years ago
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