Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
Answer: Exact Form:
−
17/
12
Decimal Form:
−
1.41
6
Mixed Number Form:
−
1 5/
12
Step-by-step explanation: brainlest please
Answer:
m = -1
Step-by-step explanation:
m = - (4 + m) + 2
m = -4 - m + 2
m = -2 - m
+m +m
2m = -2
/2 /2
m = -1
Hope this helps!
Answer:

Step-by-step explanation:
-2g=?
