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Nuetrik [128]
2 years ago
10

Algebraic factorisation simplification long question​

Mathematics
1 answer:
qwelly [4]2 years ago
3 0

Answer:Algebra Questions, for Grade 10, on simplifying, factoring, evaluating expressions and solving equations are presented along with their answers

Step-by-step explanation:

I do not know if this helps or not but here you go!

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How do I solve this
Pani-rosa [81]

Answer: you alredy solved it

Step-by-step explanation:

4 0
3 years ago
Prove this identity sin(2A)=2sinAcosA.
34kurt
The solution for proving the identity is as follows:

sin(2A) = sin(A + A) 
As sin(a + b) = sinacosb + sinbcosa, 
<span>sin(A + A) = sinAcosA + sinAcosA 
</span>
<span>Therefore, sin(2A) = 2sinAcosA

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your inquiries and questions soon. Have a nice day ahead!
</span>

7 0
2 years ago
Help please will mark Brainlyest plz help quickly
Helga [31]

Answer: 28*63

Step-by-step explanation:

- If first you want the answer, you must divide and then you would get 63.

- Then you take 63 and multiply 28 and you'll get 1,764

Hope I was able to help.

(For question 27)

8 0
3 years ago
Three students, Alicia, Benjamin, and Caleb, are constructing a square inscribed in a circle with center at point C. Alicia draw
True [87]

Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.

<h3>Inscribing a square</h3>

The steps involved in inscribing a square in a circle include;

  • A diameter of the circle is drawn.
  • A perpendicular bisector of the diameter is drawn using the method described as the perpendicular of the line sector. Also known as the diameter of the circle.
  • The resulting four points on the circle are the vertices of the inscribed square.

Alicia deductions were;

Draws two diameters and connects the points where the diameters intersect the circle, in order, around the circle

Benjamin's deductions;

The diameters must be perpendicular to each other. Then connect the points, in order, around the circle

Caleb's deduction;

No need to draw the second diameter. A triangle when inscribed in a semicircle is a right triangle, forms semicircles, one in each semicircle. Together the two triangles will make a square.

It can be concluded from their different postulations that Benjamin is correct because the diameter must be perpendicular to each other and the points connected around the circle to form a square.

Thus, Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.

Learn more about an inscribed square here:

brainly.com/question/2458205

#SPJ1

6 0
2 years ago
WORTH 50! WILL AWARD BRAINLIEST! PLEASE SHOW STEPS! THANK YOU!
yanalaym [24]

Answer:

x = 45

Step-by-step explanation:

Re-order terms so constants are on the left
15 * x/9 - 42 =28

Combine multiplied terms into a single fraction
15x/9 - 42 = 28

Cancel terms that are in both the numerator and denominator
5x/3 - 42 = 28


4 0
2 years ago
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