Question

Factor by groupingle="(4y^3 + 28y^2) + (y + 7)" alt="(4y^3 + 28y^2) + (y + 7)" align="absmiddle" class="latex-formula">

Answer 1

We have the following expression given:

$(4y^3+28y^2)+(y+7)$

We can start selecting as common factor 4y^2 and we got:

$4y^2(y+7)+(y+7)$

Now we can select y+7 as common factor and we got:

$(y+7)\left\lbrack 4y^2+1\right\rbrack$

So then our final answer would be:

$(y+7)(4y^2+1)$