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balandron [24]
11 months ago
12

Factor by grouping

le="(4y^3 + 28y^2) + (y + 7)" alt="(4y^3 + 28y^2) + (y + 7)" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Inessa05 [86]11 months ago
3 0

We have the following expression given:

(4y^3+28y^2)+(y+7)

We can start selecting as common factor 4y^2 and we got:

4y^2(y+7)+(y+7)

Now we can select y+7 as common factor and we got:

(y+7)\left\lbrack 4y^2+1\right\rbrack

So then our final answer would be:

(y+7)(4y^2+1)

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