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EastWind [94]
3 years ago
15

Help me on this question please

Mathematics
2 answers:
solong [7]3 years ago
7 0
Less than 1/2
I just want the points I’m sorry
VMariaS [17]3 years ago
3 0

Answer:

Less than 1/2

Step-by-step explanation:

Make the common denominator 60

11/12 = 55/60      7/10 = 42/60

55/60  - 42/60  = 13/ 60  

13/60 = 0.2166666667

You might be interested in
Write the equation of the circle graphed below
Mnenie [13.5K]

Answer:

Step-by-step explanation:

Comment

The basic equation of a circle is

(x - a)^2 + (y - b)^2 = r^2

a and b are the coordinates of the center of the circle

r is the radius.

Development of the equation

r = 1 - 1/2 = 1/2. r is the distance between the red dot and the blue dot.

So far what you have is (x - a)^2 + (y - b)^2 = (1/2)^2

The center is the red dot.

x = 1

y = - 1

Answer: (x - 1)^2 + (y + 1/2)^2 = 1/4

7 0
2 years ago
You help me i'll help you.
Pepsi [2]
Hi, I think the answer may be 2.
How I got my answer:
If x equals 18, divide 18 by 3 and you'll get 6, then divide 6 by the other 3 and your quotient should be 2.
Hope I helped!
5 0
3 years ago
Read 2 more answers
I need to know if this is correct
Law Incorporation [45]
Yes its right
hope this helps


7 0
3 years ago
Please help It’s due at 11:59 it’s 9:29 right now!!
yan [13]

Step-by-step explanation:

  1. 8969kg/cm^3
  2. 20oz jar of$2.78
3 0
2 years ago
Can anyone explain to me how to do this question ? ty !!​
julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0
3 years ago
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