#2) A. -7
you are correct
Answer:
The answer to your question is x = 0 and x = 1
Step-by-step explanation:
Equation
![\frac{x}{x - 2} + \frac{x - 1}{x + 1} = -1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bx%20-%202%7D%20%2B%20%5Cfrac%7Bx%20-%201%7D%7Bx%20%2B%201%7D%20%3D%20-1)
1)
![\frac{x(x + 1) + (x - 2)(x - 1)}{(x - 2)(x + 1)} = - 1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%28x%20%2B%201%29%20%2B%20%28x%20-%202%29%28x%20-%201%29%7D%7B%28x%20-%202%29%28x%20%2B%201%29%7D%20%3D%20-%201)
Expand
2) x² + x + x² - x - 2x + 2 = -1(x - 2)(x + 1)
Simplify
3) 2x² -2x + 2 = -1(x² + x - 2x - 2)
4) 2x² - 2x + 2 = -x² + x + 2
Equal to zero
5) 2x² - 2x + 2 + x² - x - 2 = 0
6) 3x² - 3x = 0
Factor
7) 3x(x - 1) = 0
8) 3x₁ = 0 x₂ - 1 = 0
9) x₁ = 0/3 x₂ = 1
10) x₁ = 0 x₂ = 1
Answer:
33 and 34
Step-by-step explanation:
Let the integers be x and x+1 respectively.
4x = 3(x+1) + 30
x = 33
therefore, the integers are 33 and 34
This is a question on forming and solving algebraic equations. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), where I post some of my own notes on certain topics and also some tips that may be useful to you :)
No, the absolute value is the distance from zero, positives and negatives don't count in absolute values, it's all about the distance.
Example: |-6| > |4|
Answer:
Hi, there the answer is 2
Step-by-step explanation: