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Eddi Din [679]
1 year ago
14

Solve the system with elimination.3x + y = 9x + 2y = 3

Mathematics
1 answer:
NikAS [45]1 year ago
5 0

In order to solve by elimination, let's multiply the first equation by -2. This way, when we add the equations, the variable y will be canceled out:

\begin{cases}-6x-2y=-18 \\ x+2y={3}\end{cases}

Now, adding the equations, we have:

\begin{gathered} -6x-2y+x+2y=-18+3\\ \\ -5x=-15\\ \\ x=\frac{-15}{-5}\\ \\ x=3 \end{gathered}

Now, calculating the value of y, we have:

\begin{gathered} x+2y=3\\ \\ 3+2y=3\\ \\ 2y=0\\ \\ y=0 \end{gathered}

Therefore the solution is (3, 0).

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t = 21 km / .5 km/hr = 42 hr

Step-by-step explanation:

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X squared = −169. A= undefined B= 13 C= ±13 D= −13
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A.   Undefined.

Step-by-step explanation:

There is no real square root of a negative number.

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3 years ago
A book falls from a shelf that is 5 feet above the floor. A model for the height h in feet if an object dropped from an initial
Brums [2.3K]

Answer:

About 0.559 seconds

Step-by-step explanation:

The height equation is:

h=-16t^2+h_0

Where h_0 is the initial height of the book, which is 5, so we can write:

h=-16t^2+5

Now, we want time it took for the book to reach ground (h = 0)

So, we substitute h = 0 and solve for t:

h=-16t^2+5\\0=-16t^2+5\\16t^2=5\\t^2=0.3125\\t=0.5590\\t=0.559

It took about 0.559 seconds for the book to reach the ground

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5-12 please it’s due in half an hour
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How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t
Zarrin [17]

By first principles, the derivative is

\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h

Use the binomial theorem to expand the numerator:

(x+h)^n=\displaystyle\sum_{i=0}^n\binom nix^{n-i}h^i=\binom n0x^n+\binom n1x^{n-1}h+\cdots+\binom nnh^n

(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

The first term is eliminated, and the limit is

\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h

A power of h in every term of the numerator cancels with h in the denominator:

\displaystyle\lim_{h\to0}\left(nx^{n-1}+\dfrac{n(n-1)}2x^{n-2}h+\cdots+nxh^{n-2}+h^{n-1}\right)

Finally, each term containing h approaches 0 as h\to0, and the derivative is

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4 0
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