All categories

3 years ago

What is the value of x? 72 84 96 252 helpppp please

Mathematics

2 answers:

Art [367]3 years ago

7 0

Its 72, which is answer A

hammer [34]3 years ago

7 0

Answer: 72

Step-by-step explanation:

We know that the sum of all exterior angles of a polygon is 360°.

Therefore, by the given picture, we have

$(x+12)^{\circ}+57^{\circ}+108^{\circ}+60^{\circ}+51^{\circ}=360^{\circ}\\\\\Rightarrow x+288^{\circ}=360^{\circ}\\\\\Rightarrow\ x=360^{\circ}-288^{\circ}\\\\\Rightarrow\ x=72^{\circ}$

Hence, the value of $=72$

You might be interested in

Evaluate 10m + n2/4 when m = 5 and n = 4

Allushta [10]

Answer:

$54$

Step-by-step explanation:

we have

$10m+\frac{n^{2}}{4}$

For $m=5.n=4$

substitute the values of m and the value of n in the equation

$10(5)+\frac{4^{2}}{4}$

$50+4$

$54$

3 0

3 years ago

If you exchange your dollars into pesos they give you 25 pesos in average for every dollar. How many pesos will they get you in

Ahat [919]

Answer:

Step-by-step explanation:

1 dollar equals to 25 pesos so if u could keep multiplying that it would soon equal to 500 on 20

1 USD = 25 pesos

1x20= 20

20x25= 500

3 0

3 years ago

What is the area of a rectangle that has sides measuring 12 centimeters and 15 centimeters?

Bess [88]

Answer:

180cm

Step-by-step explanation:

you can find the rare by multiplying the width and length. so 12 times 15 is 180.

6 0

3 years ago

Solve the equation 3(x-2)=6(5+x)

Svetach [21]

3(x - 2) =6 (5+x) (remove the parantheses)

3x - 6 + 30 + 6x (move the terms)

3x - 6x = 30 + 6 (collect like terms and calculate)

-3x = 36 (divide both sides)

x = -12

4 0

2 years ago

Is Event B dependent or independent of Event A? A: A green ball is drawn from a box with five balls and placed next to the box.

Zarrin [17]

Answer:

Step-by-step explanation:

Given that events are as follows:

A: A green ball is drawn from a box with five balls and placed next to the box. B: A red ball is drawn next and placed next to the green one

i.e. drawings of balls are made without replacement

Suppose there are m green balls and n red balls, where m+n =5

Prob of drawing green ball =m/5

After I draw made remaining are n red balls and m-1 green balls

Prob of drawing red ball now =n/4

Prob for drawing one green and one red simultaneously = $\frac{mC1*nC1}{5C2} \\= \frac{mn}{10}$

Product of the two probabilities = $\frac{m}{5} *\frac{n}{4} \\=\frac{mn}{20}$

6 0

3 years ago