These points are reflective off of the y-axis. (9,2/5) reflected over the y-axis is (9,-2/5)
Answer:
first option
Step-by-step explanation:
Given
f(x) =
← factorise the numerator
=
← cancel (x + 4) on numerator/ denominator
= 2x - 3
Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is
x = - 4
Substitute x = - 4 into the simplified f(x) for y- coordinate
f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11
The discontinuity occurs at (- 4, - 11 )
To obtain the zero let f(x) = 0, that is
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = 
There is a zero at (
, 0 )
Thus
discontinuity at (- 4, - 11 ), zero at (
, 0 )
Answer: (-8/5,0)
Step-by-step explanation: If the slope is 5, m = 5
For (-1,3) we have x₀= -1 and y₀ = 3, to find the line equation
y - y₀ = m(x - x₀)
y - 3 = 5(x - (-1))
y - 3 = 5(x + 1)
y - 3 = 5x + 5
y = 5x + 8
A P that intersects the x axis has y = 0
0 = 5x + 8
5x = -8
x = -8/5
P (-8/5,0)