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Oxana [17]
1 year ago
8

Evaluate 5 remainder 5

Mathematics
2 answers:
ExtremeBDS [4]1 year ago
8 0

The remainder is 5. To calculate this, first, divide 599 by 9 to get the largest multiple of 9 before 599. 5/9 < 1, so carry the 5 to the tens, 59/9 = 6 r 5, so carry the 5 to the digits. 59/9 = 6 r 5 again, so the largest multiple is 66. Multiply 66 by 9 to get 594, and subtract this from 599 to get 5, the remainder.

Varvara68 [4.7K]1 year ago
7 0

Answer:

22

Step-by-step explanation:

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Step-by-step explanation:

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Question 24 only. Please explain solution
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Prime factorization of 891
Fantom [35]
So exg
prime factorization is finding the prime number that will multiply to getthat tnumber
normally we exclude the number 1
so prime factor of 6=2 times 3
note:2*3 menas 2 times 3


so 891
it is odd so not divisible by 2
try 3
891/3=297
3*297=891
factor further
297
try 3
297/3=99
3*3*99=891
99
divide by 3
33
3*3*3*33
33
divide by 3
11
3*3*3*3*11
11 is prime so the prime factoization is
3*3*3*3*11 or 3^4*11
8 0
4 years ago
Read 2 more answers
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