1. Volume of 1 tennis ball = volume of sphere = 33.51 in.³
2. Volume of the cylinder = 150.8 in.³
3. Amount of space not occupied by the tennis ball = Volume of cylinder - 3(volume 1 tennis ball) = 50.27 in.³
<h3>What is the Volume of a Cylinder and Volume of a Sphere?</h3>
- Volume of Cylinder = πr²h
- Volume of Sphere = 4/3πr³
Diameter of the tennis ball = 4 in. (given)
1. Volume of 1 tennis ball = volume of sphere = 4/3πr³
r = 1/2(4 in.) = 2 in.
Volume of 1 tennis ball = 4/3π(2)³ = 33.51 in.³
2. Volume of the cylinder = πr²h
Radius of the cylinder (r) = 1/2(4 in.) = 2 in
Height of the cylinder (h) = 3(4 in.) = 12 in
Volume of the cylinder = πr²h = π(2²)(12) = 150.8 in.³
3. Amount of space not occupied by the tennis ball = Volume of cylinder - 3(volume 1 tennis ball)
= 150.8 - 3(33.51) = 50.27 in.³
Learn more about volume of a cylinder and a sphere on:
brainly.com/question/64165
Answer:
its going to be 20 years
Step-by-step explanation:
1.036
r = 1/15
a branliest from the answer will be appreciated
Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
