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OverLord2011 [107]
3 years ago
8

The sum of four consecutive even integers is 98. Which of the following equations represents this scenario?

Mathematics
2 answers:
aksik [14]3 years ago
6 0

Step-by-step explanation: To find out which of the following equations would represent the scenario of consecutive even integers, we need to understand what consecutive even integers are.

Consecutive even integers are integers but they are even so unlike consecutive integers, we skip 1 in between.

In the image provided, I have written on the whiteboard 3 numbers. If we use <em>x</em> to represent our first number, our second number can be represented as <em>x + 2</em> and our third number can be <em>x + 4</em>.

In fact any 3 consecutive even integers can be represented as X + X + 2 + X + 4.

If we have four consecutive even integers, are setup will be the same but we will go one step further and add X + 6.

Since D deals with consecutive even integers, it would be our answer.  

Helen [10]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Since it's even consecutive integers, you can say that to find the integers you skip 2.

Therefore, you would have x+2, x+4, and x+6.

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Using six random samples, the average number of catfish in the samples was 5.7. If the total population of fish in the pond is 2
zheka24 [161]
Using the proportion given, there will be 57 catfish in the pond.

The proportion given to us is
5.7/20 = x/200

Cross multiply:
5.7*200 = 20*x
1140 = 20x

Divide both sides by 20:
1140/20 = 20x/20
57 = x
5 0
3 years ago
Read 2 more answers
12x - 2y = -1<br>+ 4x + 6y= -4<br>​
svp [43]

Answer:

x = -7/40 , y = -11/20

Step-by-step explanation:

Solve the following system:

{12 x - 2 y = -1 | (equation 1)

4 x + 6 y = -4 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{12 x - 2 y = -1 | (equation 1)

0 x+(20 y)/3 = (-11)/3 | (equation 2)

Multiply equation 2 by 3:

{12 x - 2 y = -1 | (equation 1)

0 x+20 y = -11 | (equation 2)

Divide equation 2 by 20:

{12 x - 2 y = -1 | (equation 1)

0 x+y = (-11)/20 | (equation 2)

Add 2 × (equation 2) to equation 1:

{12 x+0 y = (-21)/10 | (equation 1)

0 x+y = -11/20 | (equation 2)

Divide equation 1 by 12:

{x+0 y = (-7)/40 | (equation 1)

0 x+y = -11/20 | (equation 2)

Collect results:

Answer:  {x = -7/40 , y = -11/20

6 0
3 years ago
One number is 5 times another. If their<br> difference is 96, find the numbers.
earnstyle [38]

Answer:24

Step-by-step explanation:

24*5=120.

So the difference between 120-24=96.

4 0
3 years ago
Suppose that the function f is defined. , for all real numbers, as follows.
aivan3 [116]

Answer:   <em>The values of......</em>

<em>f(-5)=\frac{9}{4}\\ \\ f(-2)= -1\\ \\ f(4)=0</em>

Step-by-step explanation:

Given function is:   \left \{ {{f(x)= \frac{1}{4}x^2 -4, if x\neq -2} \atop {=-1, if x=-2}} \right.

For f(-5),  the value of x is -5, which is not equal to -2.

So,  f(-5)= \frac{1}{4}(-5)^2 -4 = \frac{1}{4}(25)-4 =\frac{25}{4}-4=\frac{25-16}{4}=\frac{9}{4}

For f(-2),  the value of x is -2.

So,  f(-2)= -1

For f(4),  the value of x is 4, which is not equal to -2.

So,  f(4)=\frac{1}{4}(4)^2 -4 =\frac{1}{4}(16)-4 =4-4=0

5 0
3 years ago
What are the values of the coefficients and constant term of 0 = 4 – 7x2 + x in standard form?
katen-ka-za [31]

ANSWER

a =  - 7

b = 1

c = 4

EXPLANATION

The given quadratic equation is:

0 = 4 - 7 {x}^{2}  + x

We rewrite in the standard quadratic equation form to obtain,

- 7 {x}^{2}  + x + 4 = 0

Comparing this to the general standard quadratic equation.

a {x}^{2}  + bx + c = 0

We have my

a =  - 7

b = 1

c = 4

8 0
3 years ago
Read 2 more answers
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