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OverLord2011 [107]
3 years ago
8

The sum of four consecutive even integers is 98. Which of the following equations represents this scenario?

Mathematics
2 answers:
aksik [14]3 years ago
6 0

Step-by-step explanation: To find out which of the following equations would represent the scenario of consecutive even integers, we need to understand what consecutive even integers are.

Consecutive even integers are integers but they are even so unlike consecutive integers, we skip 1 in between.

In the image provided, I have written on the whiteboard 3 numbers. If we use <em>x</em> to represent our first number, our second number can be represented as <em>x + 2</em> and our third number can be <em>x + 4</em>.

In fact any 3 consecutive even integers can be represented as X + X + 2 + X + 4.

If we have four consecutive even integers, are setup will be the same but we will go one step further and add X + 6.

Since D deals with consecutive even integers, it would be our answer.  

Helen [10]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Since it's even consecutive integers, you can say that to find the integers you skip 2.

Therefore, you would have x+2, x+4, and x+6.

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Simplify |–9.23 – 1.79| – |–7.34 – 2.57|.
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11.02-9.91= 1.11

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3 years ago
The local hamburger restaurant is famous for how quickly they can assemble a burger. The restaurant advertises that its constant
melisa1 [442]

The gievn equation is ,

t=11.3h\ldots(1)

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put h = 2 in equation (1).

\begin{gathered} t=11.3\text{ (2)} \\ t=22.6 \end{gathered}

blank A assembles 2 hamburges in 22.6 seconds.

put h = 3 in equation (1)

\begin{gathered} t=11.3(3) \\ t=33.9 \end{gathered}

blank B assembles 3 hamburgers in 33.9 seconds.

put h = 5 in equation (1)

\begin{gathered} t=11.3(5) \\ t=56.5 \end{gathered}

blank C assembles 5 hamburgers in 56.5 seconds.

put h = 8 in equation (1)

\begin{gathered} t=11.3(8) \\ t=90.4 \end{gathered}

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3 0
1 year ago
Plz help me with this
Setler79 [48]

Answer:   x = 8

                (the correct answer was not provided as an option)

<u>Step-by-step explanation:</u>

log_2(x-6)+log_2(x-4)=log_2(x)\\\\log_2[(x-6)(x-4)]=log_2(x)\\\\(x-6)(x-4)=x\\\\x^2-10x+24=x\\\\x^2-11x+24=0\\\\(x-3)(x-8)=0\\\\x=3\qquad x=8\\\\\\\text{The term after the log symbol  (inside the parenthesis) must be greater than 0!}\\\\Check:\\3-6>0\ \text{FALSE --- so 3 is not a valid solution}\\\\8-6>0\ \text{TRUE}\\8-4>0\ \text{TRUE}\\8>0\ \text{TRUE --- 8 is a valid solution because it is true for all}

8 0
3 years ago
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