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1 year ago

What is the distance from P to Q ?A. 7 unitsB. 5 unitsC. 1 unitD. 25 unitshow do I find the distance from P to Q?

Mathematics

1 answer:

Alex17521 [72]1 year ago

7 0

to find the distance between 2 points we should apply the formula

$d=\sqrt[]{(x_2-x_1)^2+(y_2-_{}y_1)^2_{}}$

call point q as point 1 for reference in the formula and p as point 2

replace the coordinates in the formula

$d=\sqrt[]{(3-(-1))^2+(-4-(-1))^2}$

simplify the equation

$\begin{gathered} d=\sqrt[]{(3+1)^2+(-4+1)^2} \\ d=\sqrt[]{4^2+(-3)^2} \\ d=\sqrt[]{16+9} \\ d=\sqrt[]{25} \\ d=5 \end{gathered}$

the distance between the 2 points is 5 units

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Step-by-step explanation:

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PLEASE HELP!!!!!!!!!! What is 2^4 AND <br> 3^5

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Step-by-step explanation:

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Andrea has a goal of running at least 50 miles this month. She has already run 7 miles. How many miles does Andrea need to run e

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At least 1.72 miles per day.

Step-by-step explanation:

Given: Goal of running is at least 50 miles in a month.

Andrea have already run 7 miles.

Days left in the month is 25.

As given, Andrea have already run 7 miles.

∴ Andrea need to run this month= $50\ miles - 7\ miles= 43\ miles$

Days remaining this month is 25.

Now, finding miles need to run each day to meet her goal.

Miles need to run each day= $\frac{remaining\ miles}{remaining\ days}$

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3 years ago

A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are

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Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5 percent of these are defective.

This means that $p = 0.05$

If two items are randomly selected as they come off the production line, what is the probability that both are defective

This is P(X = 2) when n = 2. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025$

0.0025 = 0.25% probability that both are defective

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3 years ago

A math class is having a discussion on how to determine if the expressions 4x-x+5 and 8-3x-3 are equivalent using substitution.

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Answer:

option (b) is correct.

Both expressions should be evaluated with one value. If the final values of the expressions are the same, then the two expressions must be equivalent.

Step-by-step explanation:

Given : A math class is having a discussion on how to determine if the expressions 4x - x + 5 and 8 - 3x - 3 are equivalent using substitution.

We have to choose the correct method from the given options that the class has suggested.

Since we have to show the given expressions 4x - x + 5 and 8 - 3x - 3 are equivalent using substitution.

We will choose a single value of x and then evaluate both the given expression at that single value and if the output of both expression comes out to be same then the two expressions must be equivalent.

For example lets take x = 2,

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also, expression 8 - 3x - 3 becomes 8 - 3(2) - 3 = 8- 6 - 3 = 8 - 9 = -1

thus, the value is not equal hence, the two expression are not equivalent.

Thus, option (b) is correct.

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