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s344n2d4d5 [400]
3 years ago
11

Some one help pls ill make you brainliest

Mathematics
2 answers:
Andrei [34K]3 years ago
8 0

Answer:

50 dollars

Step-by-step explanation:   99.99 plus 23.51 = 123.5.  123.5 minus 73.50 = 50

monitta3 years ago
7 0

Answer:

50 dollars

Step-by-step explanation:

You are going to add 99.99 and 23.51

99.99+23.51= 123.5

Subtract 123.5 and 73.50

123.5-73.50=50

The total money he earns by mowing lawns is 50 dollars

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In a room with 10 people, how many different handshakes are possible?
Ganezh [65]
45 handshakes are possible
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3 years ago
Read 2 more answers
( 2 + 7 -14<br>Turn over​
Viefleur [7K]

Answer:

<h2>9</h2>

Step-by-step explanation:

2 + 7 - 14 flipped around =

14 - 7 + 2 =

7 + 2 =

9

<em>Hope that helps! :)</em>

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4 0
3 years ago
How do you write (243)^ 3/5 in radical form? THEN simplified?! *PLEASE HELP
SOVA2 [1]

Answer:

27

Step-by-step explanation:

If you have an exponent that is a fraction, you need to make a radical with the index from the denominator and an exponent of the radicand from the numerator.

(243)^3/5=(\sqrt[5]{243}^3)

This would come out as \sqrt[5]{14348907^}. this further simplifies down to the final answer of 27

6 0
3 years ago
Hi everyone. May you help me with this problem? I need to know how many solutions there are to this problem: -3p + 8 = -3p
masya89 [10]
-3p+8 = -3p
8= 0p
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Answer does not exist 
3 0
3 years ago
1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the
Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

f(x)=e^{3x}+\cos(5x),

g(x)=e^{3x}-\cos(5x),

h(x)=\cos(5x).

Then, letting α = 1, β= -1 and ω = -2, we see that:

\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0
3 years ago
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