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Juli2301 [7.4K]
1 year ago
6

If the average of x and y is 11 and the average of x, and y z is 5 what is the value of z

Mathematics
1 answer:
qwelly [4]1 year ago
6 0

If the average of x and y is 11 and the average of x, y and z is 5, then the value of z is -7

Given,

The average of x and y = 11

We know average = Sum of the terms / Number of terms

Then, the equation will become

\frac{x+y}{2}=11
x+y =11×2

x+y =22

Average of x, y and z = 5

\frac{x+y+z}{3}=5

x+y+z = 5×3

x+y+z =15

Substitute the value of x+y

22+z=15

z =15-22

x = -7

Hence, If the average of x and y is 11 and the average of x, y and z is 5, then the value of z is -7

Learn more about average here

brainly.com/question/12984400

#SPJ4

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Frankie and Maria paid to get into the carnival, and they had to pay a certain amount per game. Frankie played 5 games and spent
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Answer:

It cost $8 per person to get into the carnival

Step-by-step explanation:

Let the entry cost be y

Let Cost of 1 game be x

Cost of 5 games = 5x

Cost of 12 games = 12x

Frankie played 5 games and spent $15.50 altogether.

So, 5x+y=15.50 --- A

Maria played 12 games and spent $26 altogether.

So, 12x+y=26 -- B

Plot the lines

5x+y=15.50 --- Black color

12x+y=26  --- Red color

Intersection point provides the solution

(x,y)=(1.5,8)

So, it cost $8 per person to get into the carnival

6 0
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margot used 1/2 pounds of turkey to make 2/3 liters of turkey chill. If margots recipe is for 1 liter of turkey chill,how many p
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In △ABC, point D∈AC
Maslowich
<h3>Answer:</h3>
  • ABDC = 6 in²
  • AABD = 8 in²
  • AABC = 14 in²
<h3>Explanation:</h3>

A diagram can be helpful.

When triangles have the same altitude, their areas are proportional to their base lengths.

The altitude from D to line BC is the same for triangles BDC and EDC. The base lengths of these triangles have the ratio ...

... BC : EC = (1+5) : 5 = 6 : 5

so ABDC will be 6/5 times AEDC.

... ABDC = (6/5)×(5 in²)

... ABDC = 6 in²

_____

The altitude from B to line AC is the same for triangles BDC and BDA, so their areas are proportional to their base lengths. That is ...

... AABD : ABDC = AD : DC = 4 : 3

so AABD will be 4/3 times ABDC.

... AABD = (4/3)×(6 in²)

... AABD = 8 in²

_____

Of course, AABC is the sum of the areas of the triangles that make it up:

... AABC = AABD + ABDC = 8 in² + 6 in²

... AABC = 14 in²

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