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Juli2301 [7.4K]
2 years ago
6

If the average of x and y is 11 and the average of x, and y z is 5 what is the value of z

Mathematics
1 answer:
qwelly [4]2 years ago
6 0

If the average of x and y is 11 and the average of x, y and z is 5, then the value of z is -7

Given,

The average of x and y = 11

We know average = Sum of the terms / Number of terms

Then, the equation will become

\frac{x+y}{2}=11
x+y =11×2

x+y =22

Average of x, y and z = 5

\frac{x+y+z}{3}=5

x+y+z = 5×3

x+y+z =15

Substitute the value of x+y

22+z=15

z =15-22

x = -7

Hence, If the average of x and y is 11 and the average of x, y and z is 5, then the value of z is -7

Learn more about average here

brainly.com/question/12984400

#SPJ4

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A jar Contains 18 strawberry- 24cheery- and 19 lime-flavored candy the rest of the candies are chocolate there are 82 candies an
tresset_1 [31]

Answer:

61 + n = 82

Step-by-step explanation:

So the total number of candy is 82. This is the sum of each type of candy, i.e. 18 + 24 + 19 + n. So we have

18 + 24 + 19 + n = 82

61   +    n            = 82

( if we solve the equation we get n = 82 - 61 = 21)

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8 0
3 years ago
M/18=24/15 <br>how do I do this problem?
GrogVix [38]
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4 0
3 years ago
Here is a table of values y = f(x)
Rama09 [41]

A. Yes, the value of this function is 8 when x is 15.

B. False. I noted right away that the ordered pair (0,5) is not included, and some of the ordered pairs included do not represent the given function.

C. Yes, f(5) = 6. See (A) above.

D. False. The range of this function is the set of integers between 5 and 13 inclusive.

4 0
4 years ago
∆ABC is an isosceles triangle. The length of CB is 12 feet 4 inches and the congruent sides are
son4ous [18]

Answer:

Answer for 2nd is option c, for 3rd is option d, for 4th is option e

Step-by-step explanation:

As we know 1 ft.=12 in.

  1. In ΔABC

   ∴ The congruent sides are AB and AC respectively

  • CB =12 ft. 4 in.=148 in.
  • AB=\frac{3}{4}CB =111 in. =9 ft. 3 in.
  • AC=\frac{3}{4}CB =111 in. =9 ft. 3 in.

    ∵  <em>Perimeter of ΔABC</em> =AB+AC+CB

                                        =9 ft. 3 in. + 9 ft. 3 in. +12 ft. 4 in.

                                        =30 ft. 10 in.

    2. In ΔDEF

    ∴ The congruent sides are DE and DF respectively

  • DE =  6 ft. 3 in. =75 in.
  • DF =  6 ft. 3 in. =75 in.
  • Let the length of FE is equal to x
  • 0.75FE =DE =DF
  • 0.75x = 6 ft. 3 in. =75 in.
  • x =100 in. =8 ft. 4 in.

   ∵ <em>Perimeter of ΔDEF</em> =DE+DF+FE

                                        = 6 ft. 3 in. +6 ft. 3 in. +8 ft. 4 in.

                                        = 20 ft. 10 in.

    3. In ΔJKL

    ∴ The congruent sides are JL and KL respectively

  • JK = x+3
  • KL =4x-17
  • JL  =6x-45
  • JL≅KL
  • 4x-17 =6x-45  . . . . . . . . . . . . . . . . . . . . . . . (1)
  • Subracting 4x from both sides from eq 1
  • -17 =2x-45
  • Adding 45 on both the sides
  • 28 =2x
  • Dividing by 2 on both sides
  • 14 =x
  • JK = 14+3 =17
  • KL = 4×14-17 =39
  • JL = 6×14-45 =39

   ∵ <em>The dimensions of the ΔJKL are 39,39 and 17.</em>

6 0
4 years ago
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