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2 years ago

Help me with this!! Will mark Brainliest

Mathematics

1 answer:

tatiyna2 years ago

6 0

Answer:

TU = 19 cm

coz both the triangles are same.

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Please answer this question, I will give thanks and 5 stars, and, if the last question I answered isn't correct, Brainlist! If y

Nookie1986 [14]

Answer:

1/108

Step-by-step explanation:

One of the boys and one of the girls are siblings

1/9 × 1/12

1/108

4 0

3 years ago

Can someone please help me?

kvasek [131]

now, let's recall the rational root test, check your textbook on it.

so p = 18 and q = 1

so all possible roots will come from the factors of ±p/q

now, to make it a bit short, the factors are loosely, ±3, ±2, ±9, ±1, ±6.

recall that, a root will give us a remainder of 0.

let us use +3.

$\bf x^4-7x^3+13x^2+3x-18 \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{r|rrrrr} 3&1&-7&13&3&18\\ &&3&-12&3&18\\ \cline{1-6} &1&-4&1&6&0 \end{array}\qquad \implies (x-3)(x^3-4x^2+x+6)$

well, that one worked... now, using the rational root test, our p = 6, q = 1.

so the factors from ±p/q are ±3, ±2, ±1

let's use 3 again

$\bf \begin{array}{r|rrrrr} 3&1&4&1&6\\ &&3&-3&-6\\ \cline{1-5} &1&-1&-2&0 \end{array}\qquad \implies (x-3)(x-3)(x^2-x-2)$

and of course, we can factor x²-x-2 to (x-2)(x+1).

(x-3)(x-3)(x-2)(x+1).

7 0

3 years ago

What is the answer to the question 25% of what is 21?

g100num [7]

If we call the number "x" then:
x*25%=21
x*25/100=21
x=21*4
x=84

Hope this helps. :)

8 0

3 years ago

Read 2 more answers

Describe the location of the point having the following coordinates. negative abscissa, zero ordinate between Quadrant II and Qu

Marianna [84]

Answer:

The location of the point is between Quadrant II and Quadrant III

Step-by-step explanation:

we know that

The abscissa refers to the x-axis and ordinate refers to the y-axis

in this problem we have

the coordinates of the point are $(-x,0)$

see the attached figure to better understand the problem

The location of the point is between Quadrant II and Quadrant III

6 0

3 years ago

A water tank in the shape of an inverted circular cone has a base radius of 3 m and height of 7 m . If water is being pumped int

Wittaler [7]

The water level increases by 0.608 meters per minute when the water is 3.5 m deep

<h3>How to determine the rate?</h3>

The given parameters are:

Radius, r = 3
Height, h = 7
Rate in, V' = 4.3m^3/min

The relationship between the radius and height is:

r/h = 3/7

Make r the subject

r = 3h/7

The volume of a cone is;

$V = \frac 13\pi r^2h$

This gives

$V = \frac 13\pi (\frac{3h}{7})^2h$

Expand

$V = \frac{3h^3}{49}\pi$

Differentiate

$V' = \frac{9h^2}{49}\pi h'$

Make h' the subject

$h' = \frac{49}{9\pi h^2}V'$

When the water level is 3.5.

We have:

$h' = \frac{49}{9\pi * 3.5^2}V'$

Also, we have:

V' = 4.3

So, the equation becomes

$h' = \frac{49}{9\pi * 3.5^2} * 4.3$

Evaluate the products

$h' = \frac{210.7}{346.36}$

Evaluate the quotient

h' = 0.608

Hence, the water level increases by 0.608 meters per minute