Answer:

<h3>♁ Question :</h3>
- Find the distance between ( 5 , -6 ) and ( 3 ,4 ).
<h3>♁
Step by step explanation:</h3>
Let the points be A and B. Now,
- Let, A ( 5 , -6 ) ⇢ ( x₁ , y₁ )
- Let, B ( 3 , 4 ) ⇢ ( x₂ , y₂ )
Use the distance formula to determine the distance between A ( 5 , -6 ) and B ( 3 , 4 ).

Substitute the actual value of the points into the distance formula and then simplify.

Remember : The positive and negative integer are always subtracted but posses the sign of the bigger integer.

Remember : ( - ) × ( - ) = ( + )

Add the numbers : 4 and 6

Evaluate the power

Add the numbers : 4 and 100

units
Therefore , The distance between ( 5 , -6 ) and ( 3 , 4 ) is
units .
And we're done!
Hope I helped!
Have a wonderful time ! シ
~TheAnimeGirl
Answer:
C, 108
Step-by-step explanation:
rectangles
8x3 = 24
8x4 = 32
8x5 = 40
triangles
3x4 = 12
you dont really have to divide by 2 since theres two triangles
24+32+40+12 = 108
Answer:
Cosine Formula
Thus, the cosine of angle α in a right triangle is equal to the adjacent side's length divided by the hypotenuse. To solve cos, simply enter the length of the adjacent and hypotenuse and solve.
-4/5=2b
since b is alrteady in the subject of the equation simply divide both side of the equation by the coefficient of b
:. (-4/5)/2= 2b/2
-4/10=b
:. b=-2/10 or -0.4
Answer:
y = -2*x^3 - x + 2
Step-by-step explanation:
We want to solve the differential equation:
y'' + 12*x = 0
such that:
y(0) = 2
y'(0) = -1
We can rewrite our equation to:
y'' = -12x
if we integrate at both sides, we get:

Solving that integral we can find the value of y', so we will get:
y' = -12* (1/2)*x^2 + C = -6*x^2 + C
where C is the constant of integration.
Evaluating y' in x = 0 we get:
y'(0) = -6*0^2 + C = C
and for the initial value problem, we know that:
y'(0) = -1
then:
y'(0) = -1 = C
C = -1
So we have the equation:
y' = -6*x^2 - 1
Now we can integrate again, to get:
y = -6*(1/3)*x^3 - 1*x + K
y = -2*x^3 - x + K
Where K is the constant of integration.
Evaluating or function in x = 0 we get:
y(0) = -2*0^3 - 0 + K
y(0) = K
And by the initial value, we know that: y(0) = 2
Then:
y(0) = 2 = K
K = 2
The function is:
y = -2*x^3 - x + 2