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denis-greek [22]
1 year ago
9

I need help with this practice I attempted this practice previously and my attempt is in the picture

Mathematics
1 answer:
diamong [38]1 year ago
4 0

We will draw a sketch for the given triangle to find its area

The area of the triangle will be

A=\frac{1}{2}\times XY\times ZM

Since ZX = ZY = 7, then the triangle is isosceles

Then the height ZM will bisect the base XY

Then we can find ZM by using Pythagoras Theorem

\begin{gathered} ZM=\sqrt[]{7^2-3^2} \\ ZM=\sqrt[]{49-9} \\ ZM=\sqrt[]{40} \\ ZM=2\sqrt[]{10} \end{gathered}

Since XY = 6, then

The area of the triangle is

\begin{gathered} A=\frac{1}{2}\times6\times2\sqrt[]{10} \\ A=6\sqrt[]{10}\text{ square units} \end{gathered}

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Step-by-step explanation:

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6 0
3 years ago
What is the answer and how do you solve <br><br><br> 21x^3/3x^−1
Sunny_sXe [5.5K]

Answer:

  as written: 7x^2

  perhaps intended: 7x^4

Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

  \dfrac{21x^3}{3}x^{-1}=\dfrac{21}{3}x^{3-1}=7x^2

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Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

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then the simplification is ...

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The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

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6 0
3 years ago
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mixas84 [53]
Please refer the picture for the answer

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3 years ago
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Read 2 more answers
A section of a boardwalk is made using 15boards. Each board is 9/1/4 inches wide. The total width of the section is 144 inches.
sleet_krkn [62]
If there are 15 boards there are 14 gaps in-between. 
But first, 15 boards each 9 and 1/4th inches so you get  a total of 138 inches and 3/4th
If you subtract that from 144 you get 5 inches and 1/4th. The remaining amount is the total of all of the distance from the spacing.
Then you divide that by 14 (number of gaps/spacing in-between.)
So you get .375 inches. (3/8)
So width of the spacing between each board is 3/8ths of a inch
4 0
4 years ago
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