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saveliy_v [14]
1 year ago
5

A bacteria population grows by 10% every 2 years. Presently, the population is 80 000 bacteria. Find the population in 8 years f

rom now. (Can use log if needed but not “in”)
Mathematics
1 answer:
faust18 [17]1 year ago
3 0

An exponential function is modeled using the equation:

P(t)=a(1+r)^{\frac{t}{n}}

where P(t) is the population after t years, a is the initial population, r is the growth rate in decimals, t is the number of years, and n is the number of periods in one cycle.

From the given information, we have the following parameters:

\begin{gathered} a=80000 \\ r=0.1 \\ t=8 \\ n=2 \end{gathered}

Therefore, the population after 8 years can be calculated by substituting into the formula and solving for P(t) as follows:

\begin{gathered} P(t)=80000(1+0.1)^{\frac{8}{2}}=80000(1.1)^4 \\ P(t)=117128 \end{gathered}

The population is 117,128.

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