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saveliy_v [14]
1 year ago
5

A bacteria population grows by 10% every 2 years. Presently, the population is 80 000 bacteria. Find the population in 8 years f

rom now. (Can use log if needed but not “in”)
Mathematics
1 answer:
faust18 [17]1 year ago
3 0

An exponential function is modeled using the equation:

P(t)=a(1+r)^{\frac{t}{n}}

where P(t) is the population after t years, a is the initial population, r is the growth rate in decimals, t is the number of years, and n is the number of periods in one cycle.

From the given information, we have the following parameters:

\begin{gathered} a=80000 \\ r=0.1 \\ t=8 \\ n=2 \end{gathered}

Therefore, the population after 8 years can be calculated by substituting into the formula and solving for P(t) as follows:

\begin{gathered} P(t)=80000(1+0.1)^{\frac{8}{2}}=80000(1.1)^4 \\ P(t)=117128 \end{gathered}

The population is 117,128.

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topjm [15]

Answer:

EF =58

Step-by-step explanation:

from the illustration,

EF =DF - DE

<em>give</em><em>n</em><em> </em><em>that</em><em> </em><em>DF</em><em> </em><em>=</em><em>9</em><em>x</em><em>-</em><em>3</em><em>9</em><em> </em><em>,</em><em> </em><em>DE</em><em> </em><em>=</em><em>4</em><em>7</em><em> </em><em>EF</em><em>=</em><em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em>

<em>sub</em><em>stitute</em><em> </em><em>them</em><em> </em><em>into</em><em> </em><em>the</em><em> </em><em>formu</em><em>la</em><em>,</em>

<em> </em><em> </em>

<em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em><em>=</em><em>9</em><em>x</em><em>-</em><em>3</em><em>9</em><em> </em><em>-</em><em> </em><em>4</em><em>7</em>

<em>sol</em><em>ving</em><em> </em><em>for</em><em> </em><em>x</em>

<em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em><em> </em><em>=</em><em>9</em><em>x</em><em> </em><em>-</em><em>8</em><em>6</em>

<em>grou</em><em>ping</em><em> like</em><em> </em><em>ter</em><em>ms</em>

<em>3</em><em>x</em><em> </em><em>-</em><em> </em><em>9x</em><em> </em><em>=</em><em>-</em><em>8</em><em>6</em><em> </em><em>-</em><em>1</em><em>0</em>

<em>-6x</em><em>=</em><em>-</em><em>9</em><em>6</em>

<em>div</em><em>iding</em><em> </em><em>throu</em><em>gh</em><em> </em><em>by</em><em> </em><em>-</em><em>6</em>

<em>\frac{ - 6x}{ - 6}  =  \frac{ - 96}{ - 6}</em>

<em>x  =  \frac{96}{6}</em>

<em>x = 16</em>

<em>but</em><em> </em><em>EF</em><em>=</em><em>3</em><em>x</em><em>+</em><em>1</em><em>0</em>

substitute x=16 into it to get the EF

EF= 3(16)+10

EF=48+10

EF=58

6 0
3 years ago
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An instructor asked her students how much time (to the nearest hour) they spent studying for the midterm. The data are displayed
BARSIC [14]

Based on the data displayed in the histogram, the percentage of students who study 2 or more hours for the midterm is 88%.

<h3>What percentage study 2 hours or more?</h3>

First, find the number of students studying:

= 3 + 9 + 6 + 3 + 2 + 1 + 1

= 25

The number of students studying 2 or more hours for the exam are:

= 9 + 6 + 3 + 2 + 1 + 1

= 22 students

The percentage studying for two hours or more is:

= 22 / 25

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