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Korvikt [17]
1 year ago
12

Which plan to prove ∆ABD ≅ ∆CBD CANNOT be used based on the information in the diagram?

Mathematics
1 answer:
Kryger [21]1 year ago
5 0

The plan that cannot be used to prove that the two triangles are congruent based in the given information is: b. ASA.

<h3>How to Prove Two Triangles are Congruent?</h3>

The following theorems can be used to prove that two triangles are congruent to each other:

  • SSS: This theorem proves that two triangles are congruent when there's enough information showing that they have three pairs of sides that are congruent to each other.
  • ASA: This theorem shows that of two corresponding angles of two triangles and a pair of included congruent sides are congruent to each other.
  • SAS: This theorem shows that if two triangles have two pairs of sides and a pair of included angle that are congruent, then both triangles are congruent to each other.

The two triangles only have a pair of corresponding congruent angles, while all three corresponding sides are shown to be congruent to each other.

This means that ASA which requires two pairs of congruent angles, cannot be used to prove that both triangles are congruent.

The answer is: b. ASA.

Learn more about congruent triangles on:

brainly.com/question/1675117

#SPJ1

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Answer:

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That is ur correct answer

3 0
3 years ago
Read 2 more answers
The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i
kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.


Recall the formula for the sum of consecutive positive integers,

\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2

Now,

1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224

numbers, and their sum is

\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of 1+9\times2=19.

So, the sum of the first 1234 terms in the sequence is 2419.

8 0
2 years ago
Evaluate the expression 24x - 13y for x = 3 and y = 2 i need help
Vesna [10]

Answer:

46

Step-by-step explanation:

You need just substitute values of x and y, and calculate.

24x - 13y = 24*3 - 13*2 = 72 - 26 = 46

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In an experiment, the weight of several oranges were recorded in the table below. During the experiment, some of the oranges wer
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I don't think anyone can solve this without seeing the table mentioned in the question :)
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Mai's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Mai $4.10 per pound, and type B co
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