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natima [27]
3 years ago
9

Wells college in New York was once an all-girls college. I'm 2005, the college began to allow boys to enroll. By 2012, the ratio

of boys to girls was 3 to 7. If there were 200 more girls than boys in 2012, how many boys were enrolled that year?
Mathematics
1 answer:
ki77a [65]3 years ago
8 0

Answer:

<em>The number of boys enrolled was 150. </em>

Step-by-step explanation:

Suppose, the number of boys enrolled was x

As there were 200 more girls than boys, so the number of girls = x+200

Given that, the ratio of boys to girls was 3 : 7 , so the equation will be........

\frac{x}{x+200}= \frac{3}{7} \\ \\ 7x=3x+600\\ \\ 7x-3x=600\\ \\ 4x=600\\ \\ x=\frac{600}{4}=150

So, the number of boys enrolled was 150.

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Based on the results from part C, which two statements correctly interpret actions the business should take? If material 2 is us
Serjik [45]

The profit function is the difference between the cost and the revenue functions.

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<h3>How to determine the true profit functions</h3>

From the complete questions, the profit functions are calculated as follows:

<u>Material 1</u>

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<u>Material 2</u>

P(x) = 4000000 - 10000x - 160000x+ 1000x^2

P(x) = 4000000-170000x+ 1000x^2

<u>Material 3</u>

P(x) = 2000000 - 5000x - 54000x - 270x^2

P(x) = 2000000 -59000x - 270x^2

Next, we test the options

Option 1: When material 2 is used

A price is greater than $150 is $151.

Calculate P(151) using P(x) = 4000000-170000x+ 1000x^2

So, we have:

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Hence, option (1) is true

Option 2: When material 1 is used

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So, we have:

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Option 3: When material 3 is used

Calculate P(45) and P(160) using P(x) = 2000000 -59000x - 270x^2

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Read more about revenue functions at:

brainly.com/question/25638609

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m∠P = 78
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xz_007 [3.2K]

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