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3 years ago

Rational numbers to -17/10

Mathematics

1 answer:

enyata [817]3 years ago

6 0

Answer:

-17/10 is 1.7 is a rational number

Step-by-step explanation:

In mathematics, a rational number is any number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q. Since q may be equal to 1, every integer is a rational number. ... Moreover, any repeating or terminating decimal represents a rational number.

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How many milliliters are equal to 1.5 gallons, if 1 liter = 1,000 milliliters and 1 gallon = 3.785 liters?

Korvikt [17]

1.5 gallons x 3.785 liters x 1000 milliliters
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1 gallon 1 liter

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3 years ago

10. Given that the areas of the two rectangles are equal, calculate the

Virty [35]

Answer:1251231

Step-by-step explanation:

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2 years ago

I really need help with this it’s on Aleks

liraira [26]

Answer:

y = 2

Step-by-step explanation:

Given

$\sqrt[3]{3y+2}$ + 4 = 6 ( subtract 4 from both sides )

$\sqrt[3]{3y+2}$ = 2 ( cube both sides )

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3 years ago

Read 2 more answers

I’ve never been so confused, this is due in a few minutes, pls help if you can!

algol13

Given:

m(ar QT) = 220

m∠P = 54

To find:

The measure of arc RS.

Solution:

PQ and PT are secants intersect outside a circle.

<em>If two secants intersects outside a circle, then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>

$$\Rightarrow \angle P = \frac{1}{2} (m \ ar (QT) - m \ ar (RS ))$

$$\Rightarrow 54 = \frac{1}{2} (220- m \ ar (RS ))$

Multiply by 2 on both sides.

$$\Rightarrow 2 \times 54 = 2 \times \frac{1}{2} (220- m \ ar (RS ))$

$$\Rightarrow 108= 220- m \ ar (RS )$

Subtract 220 from both sides.

$$\Rightarrow 108-220= 220- m \ ar (RS )-220$

$$\Rightarrow -112= -m \ ar (RS )$

Multiply by (-1) on both sides.

$$\Rightarrow (-112)\times(-1)= -m \ ar (RS )\times(-1)$

$$\Rightarrow 112= m \ ar (RS )$

The measure of arc RS is 112.

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3 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

3 years ago