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Digiron [165]
2 years ago
8

Jason used his car as collateral to borrow money from his bank. After losing his job, Jason is now unable to make his payments.,

what is likely to happen to his car?
A) The bank will ask Jason to sell the car to help pay back his loan.
B) The bank will seize the car and likely sell it to pay off Jason's loan. THIS ONE
C) The bank will notify the local government of Jason's default on his loan, making it illegal for Jason to drive the car.
D) The bank will put a "boot" on one wheel of the car, making it un-driveable until Jason begins making his payments again.
Explain this to me please.
Mathematics
2 answers:
inna [77]2 years ago
6 0

Answer: B. The bank will seize the car and likely sell it to pay off Jason's loan.

Step-by-step explanation:

den301095 [7]2 years ago
5 0
It’s option “b”. The bank will seize the car and likely sell it to pay off a Jason’s loan
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PartA: Explain why x=6makes 4x-5< 19.
NARA [144]

Answer:

It doesn't.

Step-by-step explanation:

If you plug in 6 in the x spots you will have:

<h3>4(6)-5 < 19</h3>

If you solve that, you will get:

<h3>19< 19</h3>

So considering that they are the same number, this doesn't make sense because it should be an equal sign.

Have a nice day!!! Please mark Brainliest!

3 0
2 years ago
The square root of 61 is in between 2 integers what are they
swat32
One way is to estimate
1^2=1
2^2=4
3^2=9
4^2=16
5^2=25
6^2=36
7^2=49
8^2=64
the number 61 is between 49 and 64 therefor the square root of 61is between the intigers 7 and 8 or -7 and -8
8 0
3 years ago
PLEASE HELP ME<br> Factor each expression,<br>  2n^(2)+ 3n -2
kotegsom [21]
I would suggest factoring using the grouping method. The answer I got was (2n-1)(n+2)
5 0
3 years ago
Solve the following quadratic function
Leya [2.2K]

Answer:

x = ± 10

Step-by-step explanation:

to solve the equation let y = 0 , that is

100 - x² = 0 ( add x² to both sides )

100 = x² ( take square root of both sides )

± \sqrt{100} = x , that is

x = ± 10

8 0
2 years ago
There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In
Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

P(0.45

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

P(p>0.8)=P(z>z^*)

The z value is calculated as before:

z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0
2 years ago
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