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1 year ago

5x +6 (x-2) -8 (x-3) please help

Mathematics

1 answer:

DedPeter [7]1 year ago

8 0

Answer:

3x + 12

Step-by-step explanation:

5x + 6(x - 2) - 8(x - 3) ← distribute parenthesis

= 5x + 6x - 12 - 8x + 24 ← collect like terms

==(5x + 6x - 8x) + (- 12 + 24)

= 3x + 12

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There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

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Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

$P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}$

For the given problem it becomes

$P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}$

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

$P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\$

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

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