Ok so there are no real solutions for xy=15000 and x+y=5
there are immaginary solutions though so
xy=15000
x+y=5
x+y=5
y=5-x
x(5-x)=15000
-x^2+5x=15000
0=x^2-5x+15000
quadriacic formula
if ax^2+bx+c=0, then
x=
x^2-5x+15000
a=1
b=-5
c=15000
x=
x=
x=
x=
so the numbers are
and
Answer:
Sam made 45 rolls
Step-by-step explanation:
After giving some to his neighbor, Sam has 1 -2/5 = 3/5 of the original quantity left. After giving some to his cousin, he has (3/5)(1 -4/9) = (3/5)(5/9) of the original quantity left.
(3/5)(5/9) = 3/9 = 1/3
15 rolls = (1/3)·(original number) . . . . . . Sam has 15 roll left
45 rolls = original number . . . . . . . . . . . multiply by 3
_____
<em>Check</em>
Same gave 2/5·45 = 18 rolls to his neigbor, so had 27 left. Sam gave 4/9·27 = 12 to his cousin, so had 15 left.
Answer:
8 minutes
Step-by-step explanation:
minutes Abel completed the race = time finished - time started
7:18 - 7:10 = 8 minutes
Step-by-step explanation:
Example 1:
a+c=b+c then a=b
First let the value of a and b be different (not equal)
a=5
b=7
c=10
a+c=b+c
5+10=7+10
15≠17
Example 2:
Let the value a and b be equal (the same)
a=5
b=5
c=10
a+c=b+c
5+10=5+10
15=15
So when,
a+c and b+c is equal, a and b are <u>always</u><u> </u> equal.
Hope this helps ;) ❤❤❤
