So what your saying is that James can type 5 words and Anne can type 8 words right? And James types 150 so how many can Anne type? Is that what your asking?
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Answer: Choice A</h3>
y axis, x axis, y axis, x axis
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Explanation:
Reflecting an object over the y axis twice will have it end up in its starting position. The same can be said for the x axis as well. It doesn't matter that the x axis reflections aren't grouped next to each other, nor the y. So in a sense, two x axis reflections undo each other, so do the y axis reflections, and we end up with the same image as shown in the diagram.
Remark
The proof is only true if m and n are equal. Make it more general.
m = 2k
n = 2v
m + n = 2k + 2v = 2(k + v).
k and v can be equal but many times they are not. From that simple equation you cannot do anything for sure but divide by 2.
There are 4 combinations
m is divisible by 4 and n is not. The result will not be divisible by 4.
m is not divisible by 4 but n is. The result will not be divisible by 4.
But are divisible by 4 then the sum will be as well. Here's the really odd result
If both are even and not divisible by 4 then their sum is divisible by 4
Using pythagorean theorem:
![\begin{gathered} c^2=a^2+b^2 \\ b=\sqrt[]{c^2-a^2} \\ b=\sqrt[]{19^2-17^2} \\ b=\sqrt[]{72} \\ b\approx8.5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%5E2%3Da%5E2%2Bb%5E2%20%5C%5C%20b%3D%5Csqrt%5B%5D%7Bc%5E2-a%5E2%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B19%5E2-17%5E2%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B72%7D%20%5C%5C%20b%5Capprox8.5%20%5Cend%7Bgathered%7D)
