Arcsin x + arcsin 2x = π/3
arcsin 2x = π/3 - arcsin x
sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b)
2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx)
2x = √3/2 . cos(arcsin x) - (1/2)x)
but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²) - (1/2)x)
Reduce to same denominator:
(4x) = √3 .√(1-x²) - (x)===>5x = √3 .√(1-x²)
Square both sides==> 25x²=3(1-x²)
28 x² = 3 & x² = 3/28 & x =√(3/28)
Answer:
Step-by-step explanation:
Note that one equation has -2y and the other has +2y. The fastest solution is to add the equations together. The two terms will cancel out, eliminating the y terms.
Okay, so since her annual salary is <span>$52,750 (the amount she gets a year, all twelve months combined) you're trying to find how much she gets monthly. That would mean we would have to divide her annual salary by 12 to find her monthly salary.
</span>$52,750 ÷ 12 = 4,395.8333333333333
<span>
And since that's a (bothersome) repeating decimal, we're going to have to round it. Once rounded, you would get $</span>4,395.83. That is her monthly salary.
Answer:
5 4/5
Step-by-step explanation:
First of all subtract the whole number, 2, from 8 1/5
You would get 6 1/5
Now subtract 2/5 from that, or set up an equation like:
6 + 1/5 - 2/5
you would get 6 - 1/5 or 5 4/5
-Chetan K
