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san4es73 [151]
1 year ago
8

A bag of cookies weighs 19.1 ounces. The bag contains 50 cookies. How much does each cookie weigh?

Mathematics
1 answer:
saveliy_v [14]1 year ago
4 0

Answer: 0.382 ounces

Step-by-step explanation:

To find the unit rate of the weight of a single cookie, we will use division.

        19.1 ounces per bag / 50 cookies in the bag = 0.382 ounces per cookie

To check our work, we will multiply 0.382 ounces per cookie by 50. Since the bag, with 50 cookies, weighs 19.1 ounces, 0.382 times 50 should equal about 19.1 ounces.

        0.382 ounces * 50 cookies = 19.1 ounces ✓

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Step-by-step explanation:

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3 years ago
given that A=43 degrees , B=82 degrees and c=28, solve triangle ABC. Round to the nearest hundredth. A) C= 93 degrees , b= 33.8
n200080 [17]
A=43°
B=82°
c=28

1) A+B+C=180°
Replacing A=43° and B=82° in the equation above:
43°+82°+C=180°
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Solving for C. Subtracting 125° both sides of the equation:
125°+C-125°=180°-125°
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2) Law of sines
a/sin A=b/sin B=c/sin C
Replacing A=43°, B=82°, C=55°, and c=28 in the equation above:
a/sin 43°=b/sin 82°=28/sin 55°

2.1) a/sin 43°=28/sin 55°
Solving for a. Multiplying both sides of the equation by sin 43°:
sin 43°(a/sin 43°)=sin 43°(28/sin 55°)
a=28 sin 43° / sin 55°
Using the calculator: sin 43°=0.681998360, sin 55°=0.819152044
a=28(0.681998360)/0.819152044
a=23.31185549
Rounded to one decimal place
a=23.3

 2.2) b/sin 82°=28/sin 55°
Solving for a. Multiplying both sides of the equation by sin 82°:
sin 82°(b/sin 82°)=sin 82°(28/sin 55°)
b=28 sin 82° / sin 55°
Using the calculator: sin 82°=0.990268069, sin 55°=0.819152044
b=28(0.990268069)/0.819152044
b=33.84903466
Rounded to one decimal place
b=33.8

Answer: Option B) C=55°, b=33.8, a=23.3
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Hope this helps... mark as Brainliest plz

Step-by-step explanation:

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