The height of the isosceles triangle is 8.49 inches.
<h3>
How to find the height of the triangle?</h3>
Here we have a triangle such that two of the sides measure 9 inches, and the base measures 6 inches.
So this is an isosceles triangle.
We can divide the isosceles triangle into two smaller right triangles, such that the side that measures 9 inches is the hypotenuse, the base is 3 inches, and the height of the isosceles triangle is the other cathetus.
By Pythagorean's theorem, we can write:
(9in)^2 = (3 in)^2 + h^2
Where h is the height that we are trying to find.
Solving that for h we get:
h = √( (9 in)^2 - (3in)^2) = 8.49 inches.
We conclude that the height of the isosceles triangle is 8.49 inches.
If you want to learn more about triangles:
brainly.com/question/2217700
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The midsegment theorem says that the midsegment is half the third side and parallel as well. 20*2 is 40 so x = 35
3 ^ 3 is the same as 3 * 3 * 3
So:
3 * 3 * 3 =
(3 * 3) * 3 =
( 9 ) * 3 =
27
Answer: 141.3 in
1. V = πr
h
2. V = (3.14)(
)(5)
3. V = 141.3 in.
Hope this answer helps you!
Answer:
Step-by-step explanation:
<u>Trigonometric ratios</u>
where:
is the angle- O is the side opposite the angle
- A is the side adjacent the angle
- H is the hypotenuse (the side opposite the right angle)
Given:
- = G
- A = GF = 2
- H = EG = 4
