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andreev551 [17]
3 years ago
8

Please help! A-level maths.

Mathematics
1 answer:
astra-53 [7]3 years ago
4 0

x+y=k\implies y=k-x

Substitute this into the parabolic equation,

k-x=6-(x-3)^2\implies x^2-7x+(k+3)=0

We're told the line x+y=k intersects C twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

(-7)^2-4(k+3)=49-4(k+3)>0\implies k

We can tell from the quadratic equation that C has its vertex at the point (3, 6). Also, note that

-1\le\sin t\le1\implies3\le3+2\sin t\le5\implies3\le x\le5

and

-1\le\cos2t\le1\implies2\le4+2\cos2t\le6\implies2\le y\le6

so the furthest to the right that C extends is the point (5, 2). The line x+y=k passes through this point for 2+5=k\implies k=7. For any value of k, the line x+y=k passes through C either only once, or not at all.

So 7\le k; in set notation,

\{k\mid 7\le k

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