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topjm [15]
1 year ago
3

Solve for x to the nearest tenth.ln (x + 1) = 7

Mathematics
1 answer:
anygoal [31]1 year ago
5 0

Given that

\ln (x+1)=7

To solve for x, applying log rules

Where

\begin{gathered} \ln N=x \\ N=e^x \end{gathered}

Applying the log rule above to the given expression

\begin{gathered} \ln (x+1)=7 \\ e^{\ln (x+1)}=e^7 \\ x+1=e^7 \end{gathered}

Solve for x, i.e make x the subject

\begin{gathered} x+1=e^7 \\ x=e^7-1 \\ x=1096.63316-1 \\ x=1095.63316 \\ x=1095.6\text{ (nearest tenth)} \end{gathered}

Hence, x = 1095.6 (nearest tenth)

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