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Elina [12.6K]
3 years ago
5

Ricardo open a savings account with an initial deposit of $560 and will not make any additional deposits or withdrawals . The ac

count earns 1% simple interest. What is the total amount that Ricardo will have in his account at the end of 3 years ?
A:$168.00
B:$56.00
C:$576.80
D:$565.60
Mathematics
1 answer:
Serga [27]3 years ago
5 0

Answer:

C

Step-by-step explanation:

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What is the volume of a cylinder if ,
sergiy2304 [10]
<h3><u>Ⲁⲛ⳽ⲱⲉⲅ:</u></h3>

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<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ :</u></h3>

<u>We </u><u>are </u><u>given </u><u>that </u><u>:</u>

  • Height of cylinder = 21 cm

  • Radius of cylinder = 24 cm

<u>Therefore, Volume :</u>

➙ V = πr²h

➙ V = ( 22 / 7 ) × ( 24 )² × ( 21 )

➙ V = ( 22 / 7 ) × 576 × 21

➙ V = ( 22 × 576 × 21 ) / 7

➙ V = 266112 / 7

➙ V = 38016

‎ㅤ‎ㅤ ‎ㅤ‎ㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>volume</u><u> </u><u>of </u><u>given</u><u> </u><u>cylinder</u><u> </u><u>is </u><u>3</u><u>8</u><u>,</u><u>0</u><u>1</u><u>6</u><u> </u><u>cm³</u><u>.</u>

<h3><u>⳨ⲟⲅⲙⳙⳑⲇ ⳙ⳽ⲉ∂ :</u></h3>

The volume of cylinder is it's density which tells us the amount by which it can be filled by any material or the the amount of material which can be immersed in it.

The Formula for volume of cylinder is given by :

‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎➙ πr²h

8 0
2 years ago
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Expand using the properties and rules for logarithms
malfutka [58]

Consider expression \log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).

1. Use property

\log_a\dfrac{b}{c}=\log_ab-\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.

2. Use property

\log_abc=\log_ab+\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.

3. Use property

\log_ab^k=k\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.

4. Use property

\log_{a^k}b=\dfrac{1}{k}\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.

Answer: correct option is B.

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Answer:
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Answer:

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Step-by-step explanation:

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