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ser-zykov [4K]
3 years ago
10

A friend complains that she is always running out of money even though she “never buys anything expensive.” What advice would yo

u give her?
Computers and Technology
1 answer:
LuckyWell [14K]3 years ago
4 0
Even though she might not buy anything expensive doesn't mean she doesn't  buy a lot of things. Sometimes you buy things that aren't expensive but as you buy and buy and buy, you end up with little money.
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If you wanted to look up an article from the Chicago Tribune the best place to start would be
anyanavicka [17]
Books,well trusted websites , news.reports , schools library (online and off ) hope this helps.:-)
7 0
3 years ago
Electric Bill Problem 3.0 (20 Points) What is the total cost of using the following at /kWh? a. 1600 W air conditioner for 6h b.
gulaghasi [49]

Answer:

The total const is 13025 KWh

Explanation:

These are the steps to solve this problem:

  1. Convert all the powers from W to KW dividing by 1000.
  2. Convert all the times on minutes to hours dividing by 60.
  3. Then you can apply energy consumption formula Energy = Power*Time for any of the appliances. the results will be at KWh.
  4. Sum all the consumtions and you will have the total cost.

Attached you will have a spreadsheet as a guidance. Any  questions, just let me know.

Download xlsx
7 0
3 years ago
Explain how the internet works​
yulyashka [42]

How does the Internet Work?

The Internet works through a packet routing network in accordance with the Internet Protocol (IP), the Transport Control Protocol (TCP) and other protocols.

Hope this helps you!

5 0
3 years ago
Read 2 more answers
Create a function that will perform linear interpolation from a set of measured data stored in a list or array. The function sho
wel

Answer:

This question is incomplete, here is the complete question:

Python

a) You should create a function that will perform linear interpolation from a set of measured data. The function should take as input a list of values at which samples were taken, and then another list giving the measurements (you can assume each measurement is a single value) at those values. It should also take in a query value, and should give the best estimate it can of the value at that query. Be sure to handle values that are outside of the range, by extrapolating. You should write a program that allows you to test your function by reading the lists from a file where each line of the file is a pair of numbers separated by spaces: the value where the sample was taken, and the measurement at that value. Your program should ask the user for the name of the file and for a query value. Important: The two lists will correspond to each other: i.e. for the i-th value in the first list, the measurement will be the i-th element of the second list (these are called parallel lists or arrays). But, you should not assume that the input values are in increasing/decreasing order. That is, the values in the first list can be in any random ordering, not necessarily from smallest to largest or largest to smallest. You will have to account for this in your program, and there is more than one way to do so. You should discuss what options you can think of to handle the data arriving in any order like that, and decide what you think the best option for handling it is.

Explanation:

from __future__ import division

from cStringIO import StringIO

import numpy as np

from scipy.interpolate import RectBivariateSpline

np.set_printoptions( 1, threshold=100, edgeitems=10, suppress=True )

   # a file inline, for testing --

myfile = StringIO( """

# T P1 P2 P3 P4

0,   80,100,150,200

75, 400,405,415,430

100, 450,456,467,483

150, 500,507,519,536

200, 550,558,571,589

""" )

   # file -> numpy array --

   # (all rows must have the same number of columns)

TPU = np.loadtxt( myfile, delimiter="," )

P = TPU[0,1:] # top row

T = TPU[ 1:,0] # left col

U = TPU[1:,1:] # 4 x 4, 400 .. 589

print "T:", T

print "P:", P

print "U:", U

interpolator = RectBivariateSpline( T, P, U, kx=1, ky=1 ) # 1 bilinear, 3 spline

   # try some t, p --

for t, p in (

   (75, 80),

   (75, 200),

   (87.5, 90),

   (200, 80),

   (200, 90),

   ):

   u = interpolator( t, p )

   print "t %5.1f p %5.1f -> u %5.1f" % (t, p, u)

8 0
3 years ago
Erica has always selected large numbers of cells by clicking and dragging her mouse. A shortcut that she could use is to select
labwork [276]
D. enter because if you enter something on a cuputer or laptop your selecting something
5 0
3 years ago
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