Question

In ΔQRS, the measure of ∠S=90°, the measure of ∠R=31°, and QR = 46 feet. Find the length of SQ to the nearest tenth of a foot.

Answer 1

Answer:

$SQ=23.7\ ft$

Step-by-step explanation:

we know that

In the right triangle QRS

$sin(R)=\frac{SQ}{QR}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(31^o)=\frac{SQ}{46}$

solve for SQ

$SQ=\frac{SQ}{46}sin(31^o)=23.7\ ft$