It’s 2.03, you just put it into a calculator
Answer:

Step-by-step explanation:
x - 5 - 3x + 1 = -45
-2x - 4 = -45
-2x = -45 + 4
-2x = -41
x = 41 ÷ 2
x = 41/2
Answer:
5151.48 cms
Step-by-step explanation:
We have to:
1.68 m is 1680 cm.
Now the rope forms another right triangle. PQB, we can find the value of QB as follows:
tan (71 °) = PQ / QB
Solving:
QB = PQ / tan (71 °)
Replacing we have:
QB = 1680 / 2.9
QB = 579.31
Knowing this value we can find QA using similar triangles PQB and AQP, like this:
QA / PQ = PQ / QB
Solved:
QA = PQ ^ 2 / QB
Replacing:
QA = 1680 ^ 2 / 579.31
QA = 4872
Finally, knowing QA, we can calculate the one we want to know AP:
Sin (71 °) = AP / AB
But AB = QA + QB = 4872 + 579.31, therefore AB = 5451.31
Solved:
AP = Sin (71 °) * AB
Replacing:
AP = 0.945 * 5451.31
AP = 5151.48 cms
The triangle has sides a,b,c such that
a = 2*sqrt(5), b = sqrt(5), and c = 2*sqrt(10)
Square each value
a = 2*sqrt(5)
a^2 = (2*sqrt(5))^2
a^2 = 2^2(sqrt(5))^2
a^2 = 4*5
a^2 = 20
b^2 = 20 for similar reasons as side 'a'
c = 2*sqrt(10)
c^2 = (2*sqrt(10))^2
c^2 = 2^2*(sqrt(10))^2
c^2 = 4*10
c^2 = 40
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Using the pythagorean theorem, we see that
a^2 + b^2 = c^2
20 + 20 = 40
40 = 40
So the initial equation a^2 + b^2 = c^2 is true making the triangle with sides a,b,c defined above to be a right triangle