$\bf \cfrac{(-4x^2)(2x^{-2}y)^3}{(16x^5)(4y^3)^2}\implies \cfrac{(-4x^2)(2^3x^{-2\cdot 3}y^3)}{(16x^5)(4^2y^{3\cdot 2})}\implies \cfrac{(-4x^2)(8x^{-6}y^3)}{(16x^5)(16y^6)} \\\\\\ \cfrac{-32x^{2-6}y^3}{256x^5y^6}\implies -\cfrac{x^{-4} y^3}{8x^5y^6}\implies -\cfrac{1}{8x^5x^{4}y^6y^{-3}}\implies -\cfrac{1}{8x^{5+4}y^{6-3}} \\\\\\ -\cfrac{1}{8x^9y^3}$

8 0

3 years ago

Read 2 more answers

Everyone please answer one of these my birthday tuesday but i might be in trouble if i fail this :(

Andreas93 [3]

Answer:

11. b

10.d

9.c

7.b

1.d

the rest I can't see clearly

please give brainiest

Step-by-step explanation:

11.

3/x-4=7/x

*cross multiply

3x=7 (x-4)

3x=7x-28

28=7x-3x

28=4x

x=7

10.

SOHCAHTOA

Cos☆=11/14

cos^-1 (11/14)

☆=38.21 degrees

MLN CONGRUENT TO WBN

ML/WB=LN/BN=MN/WN

LN/BN=10/6

ML/WB

24/x=10/6

24x6=10x

144÷10

=14.4

6^2+14.4^2

=243.36

squareroot

=15.6

8 0

2 years ago

Fill in the missing values in the formula. What is the variance? 0 3.217 3.522 12.405 148.86

Lerok [7]

Answer: This’s the answer for your question 12.405

6 0

3 years ago