A percentage is really just a decimal with the point moved over
a couple of places. So what you really need is just the decimal
form of 36/48.
As always, a fraction is just a short way to say "divided by", and
when you actually go ahead and do the division indicated by the
fraction, you get the decimal.
When you divide 36 by 48, the quotient is 0.75 .
To turn a decimal into a percentage, move the point 2 places
toward the right.
0.75 = 75%
Step-by-step explanation:
its either you explain it wrong or the answer is jenny doesn't need to spend anymore money to have more baseball cards then you because she already has more then you.
You bought baseball cards at $8 for 12 cards and added them to your collection of 128 baseball cards
128+12=140
Jenny bought baseball cards at $6 for 8 and added them to her collection of 150 baseball cards
150+8=150
150>140
The answer is B. If you put the information given into a proportion, you will find that Anthony worked for 7.5 hours. When the problem says that his hourly rate is proportional to Carla's, it means that he gets the same amount of money per hour as she does.
Answer:
A polynomial is prime if it can not be factored into polynomials of lower degree also with integer coefficients.
For example, the first option:
x^3 + b*x^2 can be rewritten as:
(x - 0)*(x^2 + b*x)
So it is not prime.
The second option:
x^2 -4x - 12
Because here we can factor this into:
(x + 2)*(x - 6) = x^2 - 6x + 2*x - 12 = x^2 - 4x - 12
Now, the third option is a two variable polynomial, here the degree is equal to the sum of the degrees of both variables.
x^4 + 8*x*y^3
(x - 0)*(x^3 + 8*y^3)
So each side has a lower degree than the original polynomial, then it is not prime.
4th option:
x^2 - b^3
This can be written as:
(x + b^(3/2))*(x - b^(3/2))
Now, here we have a problem.
If for example, b = 1, this would not be a prime.
because 1^(3/2) = 1.
But if b^(3/2) is not an integer, then we can not factorize the initial polynomial into lower degree polynomials with only integer coefficients, then we can not be 100% sure that this is not a prime polynomial, then this is the correct option.