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Pachacha [2.7K]
2 years ago
3

(1 point) The expression

Mathematics
1 answer:
777dan777 [17]2 years ago
4 0

Answer:

  • n = 1/128000
  • r = -10
  • s = -3
  • t = 15

Step-by-step explanation:

You want the simplified form of (5b^1c^-5)^-3(4b^0a^2)^-5.

<h3>Rules of exponents</h3>

There are several useful rules of exponents here:

  (ab)^c = (a^c)(b^c)

  (a^b)^c = a^(bc)

  a^-b = 1/(a^b)

<h3>Application</h3>

Simplifying the top-level exponents first, we have ...

  (5b^1c^{-5})^{-3}(4b^0a^2)^{-5}=(5^{-3}b^{1(-3)}c^{(-5)(-3)})(4^{-5}b^{0(-5)}a^{2(-5)})\\\\=(5^{-3}4^{-5})a^{-10}b^{-3+0}c^{15}=\dfrac{1}{5^34^5}a^{-10}b^{-3}c^{15}=\boxed{\dfrac{1}{128000}a^{-10}b^{-3}c^{15}}

In terms of answer requirements:

  n = 1/128000

  r = -10

  s = -3

  t = 15

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