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Alex73 [517]
1 year ago
7

A rectangular floor is 7 yd long and 3 yd wide. Heatherwants to tile the floor with tile sold by the square foot.Use the facts t

o find the area in square feet.Conversion facts for length1 foot (ft) = 12 inches (in)1 yard (yd) = 3 feet (ft)1 yard (yd) = 36 inches (in)2Х5?

Mathematics
1 answer:
Sonja [21]1 year ago
5 0

We need to convert the given measures from yard to feet. Since 1 yard is equal to 3 feet, we have

\begin{gathered} 7yd=7yd\times(\frac{3ft}{1yd}) \\ \text{then} \\ 7yd=21ft \end{gathered}

similarly, for the wide, we have

\begin{gathered} 3yd=3yd\times(\frac{3ft}{1yd}) \\ 3yd=9ft \end{gathered}

Since the area of a rectangle is wide times length, the area is

\begin{gathered} A=\text{wide}\times length \\ A=9ft\times21ft \\ A=189ft^2 \end{gathered}

Therefore, the area is equal to 189 square feet

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A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li
hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20

Compute the probability that a randomly selected component needs rework as follows:

P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069}  =0.3623

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

6 0
3 years ago
ClearBags is an online company that sells packaging materials for photographers. Suppose their average order size is $208.19 wit
Andreas93 [3]

Answer:

The standard error of the mean for this sample is 9.033

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\sigma = 53.44, n = 35

So

s = \frac{53.44}{\sqrt{35}} = 9.033

The standard error of the mean for this sample is 9.033

3 0
3 years ago
Read 2 more answers
What is the answer to 153÷1/4=?
sp2606 [1]

Answer: 38.25

Step-by-step explanation: You divide the whole number by the denominator in the fraction.

153/4 = 38.25

7 0
3 years ago
Read 2 more answers
MRS.SMITH PAID#125 TO HAVE HER HAIR COLORED AND CUT. if SHE TIPS HER HAIRDRESSER 15% OF HER BILL, HOW MUCH WAS THE TIP?
Leto [7]
15% of 125 = 18.75 the tip
125 + 18.75 = 143.75  full price
Hope it helps!
5 0
3 years ago
Order the decimals 0.7 0.27 0.43 from least to greatest. Do the same thing with 0.4 0.22 0.72 what are your answers?
igor_vitrenko [27]

Answer:

0.27, 0.42, 0.7 & 0.22, 0.4, 0.72

Step-by-step explanation:

decimals 0.7 0.27 0.43 from least to greatest. Do the same thing with 0.4 0.22 0.72 what are your answers?

Arranging in ascending order ( 0.7,0.27,0.42) would be 0.27, 0.42, 0.7

This is gotten If all these decimals are converted to fractions with their denominator being 100 that is 27/100, 42/100, 70/100

Arranging in ascending order(0.4,0.22,0.72) would be 0.22, 0.4, 0.72

This is gotten If all these decimals are converted to fractions with their denominator being 100 that is 22/100, 40/100, 72/100

I hope this was helpful, please mark as brainliest

3 0
3 years ago
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