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saveliy_v [14]
1 year ago
11

Find the number of possible outcomes in the sample space. The chess club must decide when and where to meet for a practice. The

possible days are Tuesday, Wednesday, or Thursday. The possible times are 3, 4, or 5PM. There are nine classrooms available.
Mathematics
1 answer:
Lesechka [4]1 year ago
4 0

Solution

- The number of possible outcomes in the sample space is simply gotten by multiplying out all the events together.

- There are 3 possible days: Tuesday, Wednesday, or Thursday. Thus, there are 3 possible outcomes.

- There are 3 possible times: 3PM, 4PM, or 5PM. Thus, there are 3 possible outcomes again.

- There are also 9 possible classrooms available meaning another 9 possible outcomes.

- Thus, the total possible outcomes in the sample space is

3\times3\times9=81\text{ possible outcomes}

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A random number generator app on your phone generates two numbers between 0 and 8. What is the probability that the first number
aev [14]

Answer:

1/27

Step-by-step explanation:

There are 9 numbers between 0 and 8.  3 of them are less than 3 (0, 1, and 2), and 1 of them is 6.

The probability is therefore (3/9) (1/9) = 1/27.

8 0
2 years ago
84. Use properties of exponents to rewrite each expression with only positive, rational exponents. Then find the numerical value
Yakvenalex [24]

Answer:

a) 1/27

b) 16

c) 1/8

Step-by-step explanation:

a) x^{-3/2}

One of the properties of the exponents tells us that when we have a negative exponent we can express it in terms of its positive exponent by turning it into the denominator (and changing its sign), so we would have:

x^{-3/2}=\frac{1}{x^{3/2} }

And now, solving for x = 9 we have:

\frac{1}{x^{3/2}}=\frac{1}{9^{3/2} }  =\frac{1}{27}

b) y^{4/3}

This is already a positive rational exponent so we are just going to substitute the value of y = 8 into the expression

y^{4/3}=8^{4/3}=16

c) z^{-3/4}

Using the same property we used in a) we have:

z^{-3/4}=\frac{1}{z^{3/4} }

And now, solving for z = 16 we have:

\frac{1}{z^3/4} } =\frac{1}{16^{3/4} } =\frac{1}{8}

4 0
3 years ago
Write the equation of a line, in SLOPE INTERCEPT FORM, that is perpendicular to the given equation and passes through the given
adoni [48]

Step-by-step explanation:

slope interception formula is

y-y1=m(x-x1)

where m is m=y-y1/x-x1 in this case m=-2 because the line we are trying to find is parallel to the given one y=-2x-6 where slope k=-2

so the final equation would be

y-1=-2(x-(-4))

y-1=-2x-2*4

y=-2x-8+1=-2x-7

4 0
3 years ago
Which expressions are equivalent to the equation below
Irina18 [472]

Answer:

Polynomial Expression.

Step-by-step explanation:

8 0
2 years ago
Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
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